Answer:
Explanation:
From the position coordinates given , it appears that the ball moves simultaneously along x and y direction.
Displacement along x direction in one second = 4.4 - 1.8 = 2.6 m
So velocity along x direction V_x = ![\frac{2.6}{s}](https://tex.z-dn.net/?f=%5Cfrac%7B2.6%7D%7Bs%7D)
Similarly velocity along y direction V_y(1) = ![\frac{2.6}{s}](https://tex.z-dn.net/?f=%5Cfrac%7B2.6%7D%7Bs%7D)
In the next phase velocity changes both in x and y direction.
velocity in x - direction V_x(2) = [tex]\frac{2}{s}[/tex
Velocity in Y- direction V_y(2) = [tex]\frac{3.1}{s}[/tex
Acceleration in x direction = change of velocity in x direction
= ( 2 - 2.6 ) = -.6 m s⁻²
Acceleration in y direction = ( 3.1 - 2.6 ) = 0.5 m s⁻²
Total acceleration =\sqrt{( -.6 )² + ( .5 )²}
= .78 ms⁻²
gold because it has highest boiling point so it can conduct the heat
Answer:
The value of each charge is 4.22 x 10⁻⁵ C
Explanation:
Given;
distance between the two identical charges, d = 2 m
the force of repulsion between these two charges, F = 4N
Apply Coulomb's law;
![F = \frac{kq_1q_2}{r^2} \\\\but \ q_1 =q_2,then \ let \ q_1 =q_2 = q\\\\F = \frac{kq^2}{r^2}\\\\q^2 = \frac{Fr^2}{k}\\\\q^2 = \frac{4*2^2}{9*10^9} \\\\q ^2 = 1.7778*10^{-9}\\\\q = \sqrt{1.7778*10^{-9}}\\\\q =4.22 *10^{-5} C\\\\q= q_1=q_2= 4.22 *10^{-5} C](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7Bkq_1q_2%7D%7Br%5E2%7D%20%5C%5C%5C%5Cbut%20%5C%20q_1%20%3Dq_2%2Cthen%20%5C%20let%20%5C%20q_1%20%3Dq_2%20%3D%20q%5C%5C%5C%5CF%20%3D%20%5Cfrac%7Bkq%5E2%7D%7Br%5E2%7D%5C%5C%5C%5Cq%5E2%20%3D%20%5Cfrac%7BFr%5E2%7D%7Bk%7D%5C%5C%5C%5Cq%5E2%20%3D%20%5Cfrac%7B4%2A2%5E2%7D%7B9%2A10%5E9%7D%20%5C%5C%5C%5Cq%20%5E2%20%3D%201.7778%2A10%5E%7B-9%7D%5C%5C%5C%5Cq%20%3D%20%5Csqrt%7B1.7778%2A10%5E%7B-9%7D%7D%5C%5C%5C%5Cq%20%3D4.22%20%2A10%5E%7B-5%7D%20C%5C%5C%5C%5Cq%3D%20q_1%3Dq_2%3D%204.22%20%2A10%5E%7B-5%7D%20C)
Therefore, the value of each charge is 4.22 x 10⁻⁵ C
maximum allowed value of the speed in roller coaster is given as
![v = 20 m/s](https://tex.z-dn.net/?f=v%20%3D%2020%20m%2Fs)
now from kinematics we can say
![v^2 - v_i^2 = 2 a s](https://tex.z-dn.net/?f=v%5E2%20-%20v_i%5E2%20%3D%202%20a%20s)
here initial speed will be
![v_i = 0](https://tex.z-dn.net/?f=v_i%20%3D%200)
acceleration is due to gravity
![a = 9.8 m/s^2](https://tex.z-dn.net/?f=a%20%3D%209.8%20m%2Fs%5E2)
now we can use this to find the height
![20^2 - 0^2 = 2 * 9.8* h](https://tex.z-dn.net/?f=20%5E2%20-%200%5E2%20%3D%202%20%2A%209.8%2A%20h)
![400 = 19.6 *h](https://tex.z-dn.net/?f=400%20%3D%2019.6%20%2Ah)
![h = 20.4 m](https://tex.z-dn.net/?f=h%20%3D%2020.4%20m)
so maximum allowed height will be 20.4 m
Answer:
2.19 N/m
Explanation:
A damped harmonic oscillator is formed by a mass in the spring, and it does a harmonic simple movement. The period of it is the time that it does one cycle, and it can be calculated by:
T = 2π√(m/K)
Where T is the period, m is the mass (in kg), and K is the damping constant. So:
2.4 = 2π√(0.320/K)
√(0.320/K) = 2.4/2π
√(0.320/K) = 0.38197
(√(0.320/K))² = (0.38197)²
0.320/K = 0.1459
K = 2.19 N/m