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Doss [256]
2 years ago
11

A student added white crystals to a clear liquid. The crystals dissolved in the liquid. After a few seconds, the liquid became q

uite warm and then turned bright red in color. The first indication that a chemical change was taking place could be observed when----
Chemistry
1 answer:
Nuetrik [128]2 years ago
7 0

Answer:

Is when there is an increase in the temperature of the liquid

Explanation:

Increase in temperature of the liquid is an indication that chemical change occur because chemical change occur through process of chemical reaction and it involve when two or more substances combine together to form new substances which is as a result of change in chemical composition. The crystals dissolved in water to form another new solution and it became warm and this indicate a chemical change, new substances are formed as a result of increase in temperature.

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To compare the results when the independent variable is not involved
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3 years ago
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How many moles of oxygen are in 1 mole of fe(no3)3?
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One mole of Fe(NO3)3, or iron(III) nitrate, has three moles of nitrate molecules, which have three moles of oxygen atoms each. We can show this mathematically:
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3 years ago
How are heat, temperature, and thermal energy related?​
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Heat, temperature, and thermal energy are related because they all work with each other.

Explanation:

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6 0
2 years ago
A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.
BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\  &=185.59\text{ g/mol} \end{aligned}

Dimensional Analysis:

\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

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What elements are in hay
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