Answer: It will take for the concentration of A to decrease from 0.900 M to 0.210 M is 28.75 s
Explanation:
Zero order reaction : A reaction is said to be of zero order if the rate is independent of the concentration of the reactants, that means the rate is directly proportional to the zeroth power of the concentration of the reactants.
Expression for the zero order kinetics:
![[A]=-kt+[A]_o](https://tex.z-dn.net/?f=%5BA%5D%3D-kt%2B%5BA%5D_o)
where [A] = concentration left after time t = 0.210 M
![[A]_o](https://tex.z-dn.net/?f=%5BA%5D_o)
= initial concentration = 0.900 M
k= rate constant =
t = time for reaction = ?
Thus it will take for the concentration of A to decrease from 0.900 M to 0.210 M is 28.75 s
Answer:
The main function sis the 2nd one and the substance provides the first 1.
Explanation:
Hope you finish the rest on your own, have fun!
Answer:
0.717 M LiOH
Explanation:
(Step 1)
Calculate the moles of H₃PO₄ using the molarity equation.
29.15 mL / 1,000 = 0.02915 L
Molarity = moles / volume (L)
0.205 M = moles / 0.02915 L
0.00598 = moles
(Step 2)
Convert moles H₃PO₄ to moles LiOH using the mole-to-mole ratio from reaction coefficients.
1 H₃PO₄ + 3 LiOH -----> Li₃PO₄ + 3 H₂O
^ ^
0.00598 moles H₃PO₄ 3 moles LiOH
------------------------------------ x -------------------------- = 0.0179 moles LiOH
1 mole H₃PO₄
(Step 3)
Calculate the molarity of LiOH using the molarity equation.
25.0 mL / 1,000 = 0.0250 L
Molarity = moles / volume (L)
Molarity = 0.0179 moles / 0.0250 L
Molarity = 0.717 M
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Elements 2 and 4 is the answer
