2 years ago

PLZ HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

Chemistry

1 answer:

Tpy6a [65]2 years ago

5 0

This is a lab assignment, you need to do something physically to find your answers

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An atom has the following electron configuration. 1s22s22p63s23p64s? How many valence electrons does this atom have? A: 2B: 3C:

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ANSWER

2 valence electrons

STEP-BY-STEP EXPLANATION:

The electronic configuration is given below as

$1s^22s^22p^62s^23p^64s^2$

Looking at the configuration, you will see that the last energy carries 2 electrons

Hence, the valence electrons are 2

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For the chemical reaction 2HBr(aq)+Ba(OH)2(aq)⟶2H2O(l)+BaBr2(aq) write the net ionic equation, including the phases.

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Answer:

2H⁺(aq) + 2OH⁻(aq) --> 2H2O(l)

Explanation:

2HBr(aq)+Ba(OH)2(aq)⟶2H2O(l)+BaBr2(aq)

We break the compounds into ions. Only compounds in the aqueous form can be turned into ions.

The ionic equation is given as;

2H⁺(aq) + 2Br⁻(aq) + Ba²⁺(aq) + 2OH⁻(aq) --> 2H2O(l) + Ba²⁺(aq) + 2Br⁻(aq)

Upon eliminating the spectator ions; The net equation is given as;

2H⁺(aq) + 2OH⁻(aq) --> 2H2O(l)

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