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Anastasy [175]
2 years ago
13

Which type of force does a window washer want acting on him when trying to keep the same position? Question 5 options: large sma

ll balanced unbalanced.
Physics
1 answer:
taurus [48]2 years ago
8 0

The balanced force is required to be acting on the window washer to keep it in the same position.

<h3>What is Force?</h3>

The external effort causing the change in the state of motion of any object is known as force.

Forces are generally of two types namely balanced force and unbalanced force.

When an object is applied with more than one force, such that net force on the object is zero and due to this the state of motion of object remains unaffected, then such type of force is called balanced force.

Similarly, the forces on the object having some net magnitude and causing some motion to the object are known as unbalanced forces.

So as per the given problem, for keeping the window washer in the same position, it is required to apply with a balanced force.

Thus, we can conclude that balanced force is required to be acting on the window washer to keep it in the same position.

Learn more about the types of forces here:

brainly.com/question/13774406

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3 years ago
A trailer truck with a 2000 [kg] cab and a 8000 [kg] trailer is traveling on a level road at 90 [km/hr].The brakes on the traile
NeX [460]

Answer:

a)   t = 19.6 s, b) fr = 1.274 10⁴ N

Explanation:

This is a Newton's second law problem

Y Axis

for the cabin

        N₁-W₁ = 0

        N₁ = W₁

for the trailer

        N₂- W₂ = 0

        N₂ = W₂

X axis

for the cabin plus trailer, where friction is only in the cabin

         fr = (m₁ + m₂) a

the friction force equation is

        fr = μ N

we substitute

       μ N₁ = (m₁ + m₂) a

        μ m₁ g = (m₁ + m₂) a

        a = μ g    \frac{m_1}{m_1 + m_2}

         

let's calculate

         a = 0.65 9.8    \frac{2000}{2000+8000}

         a = 1,274 m / s²

a) to find the stopping distance we can use kinematics

         Let's slow down the sI system

         v₀ = 90 km / h (1000 m / 1km) (1h / 3600s) = 25 m / s

         v = v₀ - a t

when it is stopped its speed is zero

           0 = v₀ - at

           t = v₀ / a

           t = 25 / 1.274

           t = 19.6 s

b) the friction force is

           fr = 0.65 2000 9.8

          fr = 1.274 10⁴ N

This is the braking force and also the forces that couple the cars.

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A student, along with her backpack on the floor next to her, are in an elevator that is accelerating upward with acceleration a.
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Answer:

\mu_k = \frac{2(vt - L)}{(g + a) t^2}

Explanation:

As we know that backpack is kicked on the rough floor with speed "v"

So here as per force equation in vertical direction we know that

N - mg = ma

so normal force on the block is given as

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now the magnitude of kinetic friction on the block is given as

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8 0
3 years ago
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