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Anastasy [175]
2 years ago
13

Which type of force does a window washer want acting on him when trying to keep the same position? Question 5 options: large sma

ll balanced unbalanced.
Physics
1 answer:
taurus [48]2 years ago
8 0

The balanced force is required to be acting on the window washer to keep it in the same position.

<h3>What is Force?</h3>

The external effort causing the change in the state of motion of any object is known as force.

Forces are generally of two types namely balanced force and unbalanced force.

When an object is applied with more than one force, such that net force on the object is zero and due to this the state of motion of object remains unaffected, then such type of force is called balanced force.

Similarly, the forces on the object having some net magnitude and causing some motion to the object are known as unbalanced forces.

So as per the given problem, for keeping the window washer in the same position, it is required to apply with a balanced force.

Thus, we can conclude that balanced force is required to be acting on the window washer to keep it in the same position.

Learn more about the types of forces here:

brainly.com/question/13774406

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Se deja caer una moneda desde cierta altura. Si se desprecian los efectos del aire, ¿cómo varía la fuerza neta sobre la moneda a
forsale [732]

Answer:

Ok, primero pensemos en una situación normal.

La moneda comienza a caer, pero la moneda esta inmersa en una sustancia, el aire. El aire comienza a aplicar una resistencia al movimiento de la moneda, y esta resistencia incremente a medida que la velocidad de la moneda incremente. Llega un punto en el que esta nueva fuerza es igual a la fuerza gravitatoria, y en sentido opuesto, lo que causa que la fuerza neta sea 0, y que la moneda caiga a velocidad constante hasta que esta impacta con el suelo.

Ahora, en este caso tenemos que ignorar los efectos del aire, entonces no hay ninguna fuerza que se oponga a la fuerza gravitatoria, entonces la fuerza neta no cambia a medida que cae (La fuerza neta cambia cuando la moneda impacta el suelo).

También se puede analizar el caso en el que, como la fuerza gravitatoria decrece con el radio al cuadrado, a medida que la moneda cae, la fuerza gravitatoria incrementa. El tema es que en para estas dimensiones, ese cambio en la fuerza gravitacional es imperceptible,

3 0
3 years ago
Andy took a bus and then walked from his home to downtown. For the first 1.6 hour, the bus drove at an average speed of 15 km/h
Yuliya22 [10]

<em>1.6x15=24 </em>

<em> </em>

<em>0.4x4.5=1.8 </em>

<em> </em>

<em>24+1.8=25.8 </em>

<em> </em>

<em>1.6+0.4=2 </em>

<em> </em>

<em>25.8/2=12.9</em>

4 0
2 years ago
Read 2 more answers
What kind of electromagnetic radiation has the shortest wavelength? The longest?
lutik1710 [3]

Answer:

gamma is shortest, radio waves are longest

8 0
3 years ago
Calculating heat gained or lost requires mass, specific heat , and
Leto [7]
B. relative humidity
8 0
3 years ago
A car is traveling at 108 km/h, stuck behind a slower car. Finally the road is clear and the car pulls over to make a pass. The
mezya [45]

Answer:

The average acceleration of the car is 2.143 meters per square second.

Explanation:

Let assume that car accelerates uniformly, in that case, we can obtain the value of acceleration by using the following equation of motion:

v = v_{o}+a\cdot t

Where:

v_{o} - Initial velocity, measured in meters per second.

v - Final velocity, measured in meters per second.

a - Acceleration, measured in meters per square second.

t - Time, measured in seconds.

Now, we clear acceleration within expression:

a = \frac{v-v_{o}}{t}

Initial and final velocities are now converted from kilometers per hour into meters per second:

v_{o} = \left(108\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s}  \right)

v_{o} = 30\,\frac{m}{s}

v = \left(135\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s}  \right)

v = 37.5\,\frac{m}{s}

If we know that t = 3.5\,s, then, the average acceleration of the car is:

a = \frac{37.5\,\frac{m}{s}-30\,\frac{m}{s} }{3.5\,s}

a = 2.143\,\frac{m}{s^{2}}

The average acceleration of the car is 2.143 meters per square second.

8 0
3 years ago
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