Answer:
q = 1 and p = 3
Step-by-step explanation:
Since we are already given the value of x and y, then it will be easy to get what p and q is. What is needed to be done is just to insert the values of x and y in both equations
For equation 1
2x -py = 5
insert x = q and y = -1
2(q) -p(-1) = 5
2q + p = 5
for the second equation, we do same
4x + 5y + q = 0
insert x = q and y = -1
4(q) + 5(-1) + q = 0
4q -5 + q = 0
5q = 5
q = 5/5 = 1
Recall from above, 2q + p = 5
Insert q = 1, we have ;
2(1) + p = 5
2 + p = 5
p = 5-2
p = 3
Answer:
27/6, 4 3/6, or simplified version 4 1/2
Step-by-step explanation:
Always convert the mixed numbers into an improper fraction before you solve, this makes it easier to solve.
2 4/6 = 16/6
1 5/6 = 11/6
3 4/6 = 22/6
Now we solve. Remember, you do NOT add the denominator, leave it as 6 not 12. You only add the numerator.
16/6 + 11/6 = 27/6, 4 3/6 or simplified as 4 1/2
22/6 + 5/6 = The same as above.
Answer: Vertex = (2, -15) 2nd point = (0, -3)
<u>Step-by-step explanation:</u>
g(x) = 3x² - 12x - 3
= 3(x² - 4x - 1)
a=1 b=-4 c=-1
Find the x-value of the vertex by using the formula for the axis of symmetry: 


= 2
Find the y-value of the vertex by plugging the x-value (above) into the given equation: g(x) = 3x² - 12x - 3
g(2) = 3(2)² - 12(2) - 3
= 12 - 24 - 3
= -15
So, the vertex is (2, -15) ← PLOT THIS COORDINATE
Now, choose a different x-value. Plug it into the equation and solve for y. <em>I chose x = 0</em>
g(0) = 3(0)² - 12(0) - 3
= 0 - 0 - 3
= -3
So, an additional point is (0, -3) ← PLOT THIS COORDINATE
5) The relation between intensity and current appears linear for intensity of 300 or more (current = intensity/10). For intensity of 150, current is less than that linear relation would predict. This seems to support the notion that current will go to zero for zero intensity. Current might even be negative for zero intensity since the line through the points (300, 30) and (150, 10) will have a negative intercept (-10) when current is zero.
Usually, we expect no output from a power-translating device when there is no input, so we expect current = 0 when intensity = 0.
6) We have no reason to believe the linear relation will not continue to hold for values of intensity near those already shown. We expect the current to be 100 for in intensity of 1000.
8) Apparently, times were only measured for 1, 3, 6, 8, and 12 laps. The author of the graph did not want to extrapolate beyond the data collected--a reasonable choice.
Answer:
The answer to your question is Judaism, Christianity, Islam.
Step-by-step explanation: