There are many ways to test and identify metal. The easiest way is observing its color. Also how reflective it is. Other ways would be boiling point, melting point, density, or conductivity of the metal.
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8 0

3 years ago

Part APart complete A sample of sodium reacts completely with 0.568 kg of chlorine, forming 936 g of sodium chloride. What mass

yan [13]

Answer: 368 grams of sodium reacted.

Explanation:

The balanced reaction is :

$2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)$

$\text{Moles of chlorine}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of chlorine}=\frac{0.568\times 1000g}{71g/mol}=8moles$

$\text{Moles of sodium chloride}=\frac{936g}{58.5g/mol}=16mol$

According to stoichiometry :

2 moles of $NaCl$ are formed from = 2 moles of $Na$

Thus 16 moles of $NaCl$ are formed from= $\frac{2}{2}\times 16=16moles$ of $Na$

Mass of $Na=moles\times {\text {Molar mass}}=16moles\times 23g/mol=368g$

Thus 368 grams of sodium reacted.

4 0

3 years ago

Please help me, I really need it, God Bless you <3

gladu [14]

$\\ \sf\longmapsto {}^{88}_{38}Sr^{2+}$

As 2 electrons are donated Hence the No of electrons =38-2=36

$\\ \sf\longmapsto {}^{51}_{23}V^{3+}$

As 3 electrons donated the no of electrons=23-3=20

$\\ \sf\longmapsto {}^{55}_{26}Fe^{3+}$

No of neutrons=55-26=29

$\\ \sf\longmapsto {}^{112}_{48}$

As 2 electrons are donated no of electrons =48-2=46

$\\ \sf\longmapsto {}^{210}_{82}Pb^{2+}$

No of neutrons=210-82=128

7 0

2 years ago