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8090 [49]
3 years ago
5

Elements that are arranged in the same column on the periodic table belong to the same family of elements. the atoms of elements

in the same family all have the same number of valence _______ in their outer shell.
a. protons
b. neutrons
c. electrons
d. all of these
Chemistry
1 answer:
Vlad [161]3 years ago
4 0
The answer is: c. electrons
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Intermolecular forces allow which of the following substances to be the least fluid?
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Which atom gives up its electrons most easily?<br><br> THE ANSWER IS “Rb”
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Before any reaction occurs, the concentration of A in the reaction below is 0.0510 M. What is the equilibrium constant if the co
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0.0119

Explanation:

There was a part missing. I think this is the whole question:

<em>Before any reaction occurs, the concentration of A in the reaction below is 0.0510 M. What is the equilibrium constant if the concentration of A at equilibrium is 0.0153 M?</em>

A (aq) ⇌ 2B (aq) + C(aq)

<em>Remember to use correct significant figures in your answer. Do not include units in your response.</em>

First, we have to make an ICE Chart, which stands for initial, change and equilibrium. We will call "x" unknown concentrations.

        A (aq) ⇌ 2B (aq) + C (aq)

I       0.0510       0            0

C         -x          +2x          +x

E    0.0510-x     2x            x

Since the concentration at equilibrium of A is 0.0153 M, we get

0.0510 - x = 0.0153 \\x = 0.0357

We can use the value of x to calculate the concentrations at equilibrium.

[A]e = 0.0153 M \\[B]e = 2x = 2(0.0357) = 0.0714 M \\[C]e = x = 0.0357 M \\

The equilibrium constant, Kc, is the ratio of the equilibrium concentrations of products over the equilibrium concentrations of reactants each raised to the power of their stoichiometric coefficients.

Kc = \frac{[B]^{2}  \times [C]}{[A]} = \frac{0.0714^{2}  \times 0.0357}{0.0153} = 0.0119

The equilibrium constant for this reaction at equilibrium is 0.0119.

You can learn more about equilibrium here: brainly.com/question/4289021

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