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daser333 [38]
2 years ago
14

4b) Work out the mean and standard deviation of the following: picture included

Mathematics
1 answer:
Jlenok [28]2 years ago
4 0

Answer:

Yes, your simultaneous equations are correct;

Solve them like so:

170 + 1.6449σ = 180 - 0.8416

2.4865σ = 10

σ = 4.0217...

μ = 170 + 1.6449(4.0217...)

μ = 176.615...

MS is correct, you must've made an error in solving or rearranging

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Prove that given any 17 integers, there exist nine of them whose sum is divisible by 9.
vaieri [72.5K]

This is a simple consequence of the Zero-sum problem: https://en.wikipedia.org/wiki/Zero-sum_problem

7 0
3 years ago
Read 2 more answers
A job candidate at a large job fair can be classified as unacceptable, provisional, or acceptable. Based on past experience, a h
svp [43]

Answer:

chisquare = 31.667

degree of freedom = 2

Step-by-step explanation:

Formula for chisquare test =  (O-E)²/E

total number observations= 60 + 25 + 15 = 100                  

Estimated E,

80% x 100 = 80

15%x100 = 15

5% x 100 = 5

chisquare =

\frac{(60-80)^{2} }{80} +\frac{(25-15)^{2} }{15}+\frac{(15-5)^{2} }{5}\\

= 5 + 6.67 + 20

= 31.667

from the calculation above the value of the chisquare statistic = 31.67

the degree of freedom is the number of samples in the test  n - 1

= 3-1

= 2

I have solve this question also in a tabular form to aid understanding in the file i uploaded.

thank you and good luck!

4 0
3 years ago
What is log6 8+ log6 27
defon
\log_6 8 + \log_6 27=\log_6 (8 \times 27)=\log_6 216=3
7 0
3 years ago
Read 2 more answers
03.03 mc) find the ordered pairs for the x- and y-intercepts of the equation 5x − 6y = 30 and select the appropriate option belo
Archy [21]
5x - 6y = 30

to find x intercept, sub in 0 for y
5x - 6(0) = 30
5x = 30
x = 30/5
x = 6......so the x intercept is (6,0)

to find the y intercept, sub in 0 for x
5(0) - 6y = 30
-6y = 30
y = 30/-6
y = -5...so the y intercept is (0,-5)
6 0
3 years ago
I need help with #6!! Thanks
tatyana61 [14]
Use this formula:  d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }

a)  d=11

Work:
d=sqrt((4-(-7))^2+(5-5)^2
d=sqrt((11)^2+(0)^2)
d=sqrt(121+0)
d=sqrt(121)
d=11

b) d=4

c) d = 16

d) d=160

e) d=12
6 0
3 years ago
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