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Fofino [41]
2 years ago
13

WILL GIVE BRAINLIEST!!

Mathematics
1 answer:
allsm [11]2 years ago
6 0

Answer:

It is the first one I am pretty sure about it gl for the results of this exam

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What is the least number you could multiply by to write an equivalent equation with integer coefficients?
Helga [31]
The least common multiple of the divisors 3 and 2 is 6. Multiplying by 6 gives you
  2(4a+1) = 3a

Multiply both sides of the equation by 6.
5 0
3 years ago
lled a 12:3:112:3:1 ratio. Such a model can provide the basis for the null hypothesis in a significance test. A cross of white a
nadezda [96]

Here is the full question:

When a species has several variants of a phenotype passed on from generation to generation, we can form a hypothesis about the genetics of the trait based on Mendelian theories of genetic inheritance. For example, in a two-gene dominant epistatic model, the first gene masks the effect of the second gene, leading to the expression of three phenotype variants. Crossing the dominant and recessive homozygote lines would result in a second generation represented by a mix of dominant, intermediate, and recessive phenotype variants in the expected proportions: and respectively, also called a 12:3: 1 ratio.

Such a model can provide the basis for the null hypothesis in a significance test. A cross of white and green summer squash plants gives the number of squash in the second generation F2: 131 white squash, 34 yellow squash, and 10 green squash. Are these data consistent with a 12: 3: 1 dominant epistatic model of genetic inheritance( white being dominant)?

The null hypothesis for the chi-square goodness-of-fit test is  <u>               </u>

Answer:

The null  hypothesis for the chi-square goodness-of-fit test is :

\mathbf{H_o:p_{white} = \frac{12}{16}, p_{yellow} = \frac{3}{16}; p_{green} = \frac{1}{16}           }

Step-by-step explanation:

The objective of this question is to state the null hypothesis for the  chi-square goodness-of-fit test.

Given that:

There are three colors associated with this model . i,e White , yellow and green and they are in the ratio of 12:3:1

The total number of these color traits associated with this model = 12 + 3 + 1 = 16

Thus ;

The null  hypothesis for the chi-square goodness-of-fit test is :

\mathbf{H_o:p_{white} = \frac{12}{16}, p_{yellow} = \frac{3}{16}; p_{green} = \frac{1}{16}           }

3 0
3 years ago
What is the mode of 156 157 158 159 160 161 162 163 164 165
xenn [34]

Answer:

There is no mode in this sequence.

Step-by-step explanation:

The mode is the most frequent number.

In your case, we can analyze the set:

156, 157, 158, 159, 160, 161, 162, 163, 164, 165

Since these are all straightforward consecutive integers, there are no recurring numbers.

Thus, there is no mode in this sequence.

5 0
3 years ago
Read 2 more answers
Numbers less than 20 which have exacly 3 factors pls!
Lana71 [14]

Answer:

9,40 is the answer of your question

3 0
2 years ago
Read 2 more answers
g The distribution of heights of 7-year-old girls is approximately normally distributed with a mean of 47.7 inches and a standar
Lana71 [14]

Answer:

a) 90th percentile

b) X = 51.43 ( Sophia's height ) , Amy's height = 50.92

c)  0.2394

d)  46.44 inches

Step-by-step explanation:

mean value( <em>u</em> ) = 47.7 inches

std ( σ )= 2.4 inches

Amy height = 1.34 std above mean value

Sophia height = 94th percentile of height distribution

A ) what percentile is Amy's height

To Calculate the percentile of Amy's height

P( X ≤  50.916   ) = P( (X-µ)/σ )  ≤  (50.916-47.7) /2.4)  

=P(Z ≤  1.340  ) = 0.9099  = 90th percentile

B) How Amy's height compare to Sophia's

The proportion given based on Sophia's height = 0.94

z -value at the proportion ( 0.94 ) = 1.55 ( from excel )

note z-value can be calculated using  =  ( x - µ ) / σ                      

therefore: X (Sophia's height )  = zσ + µ=   (1.55 * 2.4)  +  47.7  

 X = 51.43 ( Sophia's height ) , Amy's height = 50.92

C) percentage expected to be taller than 49.4 inches

P ( X ≥ 49.40  ) = P( (X-µ)/σ)  ≥ (49.4-47.7) / 2.4)              

= P(Z ≥ 0.708 )

= P( Z <  -0.708   )

= 0.2394

D) Below what height are the shortest 30% of 7-year old girls

( <em>u</em> ) = 47.7 inches

std ( σ )= 2.4 inches

given proportion = 30% = 0.3

The z value at 0.3 = -0.52 ( from excel )

to calculate for X ( height ) we have to apply the formula used to determine z value

z= (x-µ) /σ

hence : X = (Z * σ)  +<em> u = </em>(-0.52 * 2.4 ) + 47.7

            X = 46.44

below 46.44 inches lies about 30% of 7 year old girls height

6 0
3 years ago
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