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andrezito [222]

2 years ago

13

The primary reason the angle of attack must be increased, to maintain a constant altitude during a coordinated turn, is because

the

1 answer:

Tems11 [23]2 years ago

5 0

As a result of the bank, the vertical component of the lift has lessened.

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De onde veio o dinheiro para financiar a indústria no Brasil a partir de 1930?

liq [111]

Answer: Descomponiendo los ingresos de Brasil, encontramos que se derivan de los siguientes tres sectores: agricultura, industria y servicios. Según estimaciones de 2014, el 5,8% de los ingresos de Brasil provino de la agricultura, el 23,8% de la industria y el 70,4% de los servicios.Durante las décadas de 1940 y 1950, el gobierno brasileño comenzó a construir acerías, refinerías de petróleo y represas hidroeléctricas. ... Brasil se encuentra entre las principales naciones industriales del mundo, debido al gasohol.

Explanation:

4 0

3 years ago

A ball is hit 1 meter above the ground with an initial speed of 40 m/s. If the ball is hit at an angle of 30 above the horizonta

Vika [28.1K]

Answer:

$t_t=4.131\ s$

Explanation:

Given:

height above the horizontal form where the ball is hit, $y=1\ m$

angle of projectile above the horizontal, $\theta=30^{\circ}$

initial speed of the projectile, $u=40\ m.s^{-1}$

<u>Firstly we find the </u><u>vertical component of the initial velocity</u><u>:</u>

$u_y=u.\sin\theta$

$u_y=40\times \sin30^{\circ}$

$u_y=20\ m.s^{-1}$

During the course of ascend in height of the ball when it reaches the maximum height then its vertical component of the velocity becomes zero.

So final vertical velocity during the course of ascend:

$v_y=0\ m.s^{-1}$

Using eq. of motion:

$v_y^2=u_y^2-2g.h$ (-ve sign means that the direction of velocity is opposite to the direction of acceleration)

$0^2=20^2-2\times 9.8\times h$

$h=20.4082\ m$ (from the height where it is thrown)

<u>Now we find the time taken to ascend to this height:</u>

$v_y=u_y-g.t$

$0=20-9.8t$

$t=2.041\ s$

<u>Time taken to descent the total height:</u>

we've total height, $h'=h+y$ $=20.4082+1$

$h'=u_y'.t'+\frac{1}{2} g.t'^2$

during the course of descend its initial vertical velocity is zero because it is at the top height, so $u_y'=0\ m.s^{-1}$

$21.4082=0+4.9t'^2$

$t'=2.09\ s$

<u>Now the total time taken by the ball to hit the ground:</u>

$t_t=t'+t$

$t_t=2.09+2.041$

$t_t=4.131\ s$

3 0

3 years ago

A pool and stops at the

Bas_tet [7]

In Linear motion the swimmer swims

8 0

3 years ago

Infrasounds _____.

LiRa [457]

Infra sounds are sounds with frequencies below 20 Hz.The popular concept that infra sounds are in audible holds false

Explanation:

Some example of Infrasounds are- some animals such as whales, elephants and giraffes which communicate with each other using infrasound over long distances.
Various natural phenomenon such as Avalanches, volcanoes, earthquakes, ocean waves, water falls and meteors also generate infrasonic waves
Infrasound, is sound that is lower in frequency than 20 Hz or cycles per second.
Even the human body can generate mechanical vibrations at very low frequencies, which are known as the infrasonic waves. Such low-frequency vibrations/infrasonic waves are produced by physiological processes—such as heartbeats, respiratory movements, blood flow in vessels, and other processes.

5 0

3 years ago

A steel wire of diameter 1 mm can support a tension of 0.24 kn. suppose you need a cable made of these wires to support a tensio

forsale [732]

Assuming the same deformation and elastic modulus, we can use the relationship:
(P/D)1 = (P/D)2
Where P is the load, Dis the diameter of the wire, 1 is the first wire, and 2 is the second wire. Using the given values and solving for the diameter of the second wire:
D = (24 / 0.24) (1)
D = 100 mm

4 0

3 years ago