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Bezzdna [24]
2 years ago
9

Find the magnitude of the vector <−4, −6>. 8 7.2 10 6.4

Mathematics
1 answer:
PolarNik [594]2 years ago
4 0

The magnitude of the vectors is 7.2

The magnitude of a vector is resolved by using a formula

<h3>Magnitude of a Vector</h3>

This is the displacement between two vectors and can be calculated as

x^2 = y^2 + z^2\\x = \sqrt{y^2 + z^2} \\

where x is the magnitude of displacement between y and z.

In this question, the vectors are

  • -4
  • -6

Let's find the magnitude of this vector

x = \sqrt{(-4)^2+(-6)^2}\\x = \sqrt{16+36}\\x = \sqrt{52}\\x = 7.2

The magnitude of the vectors is 7.2

Learn more on magnitude of vectors here;

brainly.com/question/3184914

brainly.com/question/8536161

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Answer:

Step-by-step explanation:

ummm what there is no question!

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2 years ago
I need help with this math equation 3(2x + 6)
My name is Ann [436]

Answer:

6+18 pls give brainlest

Step-by-step explanation:

How to solve your problem

3(2+6)

Simplify

1

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3(2+6)

6+18

Solution

6+18

7 0
3 years ago
Can you tell me what X=
mihalych1998 [28]

Answer:

x = 21 degrees!

Step-by-step explanation:

3x + x + 96 = 180

4x +96 = 180

Subtract 96 from both sides!

4x = 84

Divide by 4 from both sides!

x = 21 degrees

4 0
2 years ago
Read 2 more answers
Six friends equally share the cost of a gift. They pay $90 and receive $42 in charge . How much does each friend pay?
sergij07 [2.7K]

Answer:

$8.00

Step-by-step explanation:

Let's set up the equation first.

What do we know:

1. We have 6 friends spliting the costs of the gifts

2. After purchasing the gifts they have $42 in change

3. They originally had $90 to spend.

Equation:

6f + $42 = $90

Next: Subtract the $42 from each side and we are left with:

6f = $48

Divide both sides by 6 and we are left with

f = $8

Since f represented the cost each friend spent our answer is $8.00

3 0
2 years ago
Is my answer correct or no? <br> ---&gt; show explanation &amp; details if i am wrong!!!
neonofarm [45]

Answer:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle ⇒ 3rd answer

Step-by-step explanation:

From the graph of the circle

∵ The center of the circle F is at the origin

∴ F is (0 , 0)

∵ The circle passes through point (7 , 0)

- The length of the radius of the circle is the distance between

   the center of the circle and a point on the circle

∴ r is the distance between points (0 , 0) and (7 , 0)

∴ r=\sqrt{(7-0)^{2}+(0-0)^{2}}=\sqrt{49}=7

∴ The length of the radius of the circle is 7 units

Let us find the distance between point (7 , -7) and the origin (0 , 0)

  • If the distance is equal to the radius of the circle, then the point is on the circle
  • If the distance is greater than the radius, then the point is outside the circle
  • If the distance is less than the radius, then the point is inside the circle

∵ The distance =  \sqrt{(7-0)^{2}+(-7-0)^{2}}=\sqrt{49+49}=\sqrt{98}=7\sqrt{2}

∵ r = 7

∵ 7\sqrt{2} > 7

∴ The distance is greater than the radius of the circle

∴ Point (7 , -7) lies outside the circle

The correct answer is:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle

<em>Your answer is not correct, the correct answer is the 3rd answer</em>

3 0
3 years ago
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