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Bezzdna [24]
2 years ago
9

Find the magnitude of the vector <−4, −6>. 8 7.2 10 6.4

Mathematics
1 answer:
PolarNik [594]2 years ago
4 0

The magnitude of the vectors is 7.2

The magnitude of a vector is resolved by using a formula

<h3>Magnitude of a Vector</h3>

This is the displacement between two vectors and can be calculated as

x^2 = y^2 + z^2\\x = \sqrt{y^2 + z^2} \\

where x is the magnitude of displacement between y and z.

In this question, the vectors are

  • -4
  • -6

Let's find the magnitude of this vector

x = \sqrt{(-4)^2+(-6)^2}\\x = \sqrt{16+36}\\x = \sqrt{52}\\x = 7.2

The magnitude of the vectors is 7.2

Learn more on magnitude of vectors here;

brainly.com/question/3184914

brainly.com/question/8536161

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Identify the variables in the expression 4mn + 6m - 3
pychu [463]

Hey there! I'm happy to help!

A variable is a letter or symbol used to represent an unknown number.

We see two letters here: m and n. Therefore, those are the variables.

Have a wonderful day! :D

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3 years ago
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3 years ago
Group points {(0,1),(0,5)(2,6),(3,3)}is not a function, but group points {(1,4)(2,7)(3,1)(5,7)} is a function. What do you notic
Tasya [4]
<h2>Any value in the domain of the function should have a unique value in codomain.</h2>

Step-by-step explanation:

In the first set of points \{\text{(0,1),(0,5)(2,6),(3,3)}\},

value 0 maps to two distinct values 1,5 in the codomain.

This violates the property of functions.

The first set of points does not form a function.

In the second set of points \{\text{(1,4),(2,7)(3,1),(5,7)}\},

Every value in domain corresponds to unique value in domain.

There is no violation in the property of functions.

The second set of points does form a function.

6 0
2 years ago
Graph the function by the table. Is the function linear or nonlinear?
nikitadnepr [17]
The answer is Nonlinear.
6 0
3 years ago
Read 2 more answers
Hopefully someone can see this time, please help
cricket20 [7]

Answer:

m = -1

Step-by-step explanation:

The slope of the line is -1

3 0
2 years ago
Read 2 more answers
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