Answer:
∀s ∈ D, C(s) - - - > E(s)
∀s ∈ D, C(s) - - - > ~ E(s)
∃s ∈ D such that M(s) ∧ C(s)
Step-by-step explanation:
D = set of all students
M(s) = s math major
C(s) = s Computer science major
E(s) = s Engineering major
Expressing the following using quantifies variables and predicates :
A.) Every computer science student is an engineering student
∀s ∈ D, C(s) - - - > E(s)
b. No computer science students are engineering students
∀s ∈ D, C(s) - - - > ~ E(s)
c. Some computer science students are also math majors
∃s ∈ D such that M(s) ∧ C(s)
∃s = Existential Domain
∀s = universal
∧ = connective and
~ = not
∈ = belongs to
Answer:
7/6
Step-by-step explanation:
22.9 is the closest but not exact. It was probably rounded off.
I used the formula: leg^2+leg^2=hypotenuse^2
(You can use that formula for any right triangle.)
Answer:
- 1/4
Step-by-step explanation:
Where you see X, substitute with 1/3
Solve the power/exponent first:
6(1/3) = 2
That is ; - 4(1/4)^2
Solve the parenthesis:
(1/4)^2 = 1/16
-4(1/16)
= - 1/4
Answer:
0.589
Step-by-step explanation:
THis is a conditional probability question. Let's look at the formula first:
P (A | B) = P(A∩B)/P(B)
" | " means "given that".
So, it means, the <u><em>"Probabilty A given that B is equal to Probability A intersection B divided by probability of B."</em></u>
<u><em /></u>
So we want to know P (Female | Undergraduate ). This in formula is:
P (Female | Undergraduate) = P (Female ∩ Undergraduate)/P(Undergraduate)
Now,
P (Female ∩ Undergraduate) means what is common in both female and undergraduate? There are 43% female that are undergrads. Hence,
P (Female ∩ Undergraduate) = 0.43
Also,
P (Undergraduate) is how many undergrads are there? There are 73% undergrads, so that is P (undergraduate) = 0.73
<em>plugging into the formula we get:</em>
P (Female | Undergraduate) = P (Female ∩ Undergraduate)/P(Undergraduate)
=0.43/0.73 = 0.589
this is the answer.