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In-s [12.5K]
2 years ago
7

If a ball is dropped off a tall building and accelerates at 9.8 m/s^2 until reaching the ground at a speed of 55 m/s, how long w

ill it take for the ball to reach the ground?
Physics
1 answer:
bearhunter [10]2 years ago
8 0

Answer:

5.61s

Explanation:

\pink{\frak{Given}}\begin{cases} \textsf{ A ball is dropped off a tall building and accelerates at 9.8 m/s$^2$ .}\\\textsf{It reaches the ground at a speed of 55 m/s .} \end{cases}

And we need to find out the time taken by the ball to reach the ground .

  • The initial velocity of the ball will be 0 since it is dropped .

Here we can use the First equation of motion , namely ;

\sf \longrightarrow v = u + at

where the symbols have their usual meaning . Now substituting the respective values , we have,

\sf \longrightarrow 55m/s = 0m/s + 9.8 m/s^2(t)\\

\sf \longrightarrow 55m/s = 9.8m/s^2(t)\\

\sf \longrightarrow t = \dfrac{55m/s}{9.8m/s^2}\\

\sf \longrightarrow \boxed{\bf time = 5.61 s }

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