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In-s [12.5K]
2 years ago
7

If a ball is dropped off a tall building and accelerates at 9.8 m/s^2 until reaching the ground at a speed of 55 m/s, how long w

ill it take for the ball to reach the ground?
Physics
1 answer:
bearhunter [10]2 years ago
8 0

Answer:

5.61s

Explanation:

\pink{\frak{Given}}\begin{cases} \textsf{ A ball is dropped off a tall building and accelerates at 9.8 m/s$^2$ .}\\\textsf{It reaches the ground at a speed of 55 m/s .} \end{cases}

And we need to find out the time taken by the ball to reach the ground .

  • The initial velocity of the ball will be 0 since it is dropped .

Here we can use the First equation of motion , namely ;

\sf \longrightarrow v = u + at

where the symbols have their usual meaning . Now substituting the respective values , we have,

\sf \longrightarrow 55m/s = 0m/s + 9.8 m/s^2(t)\\

\sf \longrightarrow 55m/s = 9.8m/s^2(t)\\

\sf \longrightarrow t = \dfrac{55m/s}{9.8m/s^2}\\

\sf \longrightarrow \boxed{\bf time = 5.61 s }

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An object is moving east, and its velocity changes from 65 m/s to 25 m/s in 10 seconds. Which describes the acceleration? negati
hammer [34]

Answer:

we could use the formula, v=u+at,

65=25+a (10), a=4 , since the motion is declerating we have a=-4 m/s2

5 0
3 years ago
What are basic physical quantities and it's measurement units? Make a chart.
jolli1 [7]

Displacement/distance metres
Time seconds
Force Newtons
Energy Joules
Voltage Volts
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Light intensity Candella
Pressure Pascals
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8 0
2 years ago
If the relative humidity is 25 nd the saturation mixing ratio is 24g/kg, what is the mixing ratio?
levacccp [35]

The mixing ratio is 6.

To find the answer, we have to know about the mixing ratio.

<h3>What is mixing ratio?</h3>
  • The mixing ratio must be calculated in a complex manner.
  • A saturated vapor pressure (es) for values of air temperature and an actual vapor pressure (e) for values of dewpoint temperature must be determined in order to determine the mixing ratio.
  • The air temperature and/or dewpoint temperature must first be converted to degrees Celsius (°C) before the vapor pressures can be calculated.
  • The equation below can be used to determine the relative humidity (rh), as well as the actual mixing ratio and saturated mixing ratio,

                         Rh=\frac{w}{w_s} *100

where; w is the mixing ratio and w(s) is the saturation mixing ratio.

  • In our question, it is given that,

                                    Rh=25\\w_s=24

  • Thus, the mixing ratio will be,

                            w=\frac{Rh*w_s}{100} =\frac{25*24}{100}=6

Thus, we can conclude that, the mixing ratio is 6.

Learn more about mixing ratio here:

brainly.com/question/8791831

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5 0
1 year ago
If the charge on the negative plate of the capacitor is 121 nano-Coulomb, how many excess electrons are on that plate? Write you
Julli [10]

Answer:

n = 756.25 giga electrons

Explanation:

It is given that,

If the charge on the negative plate of the capacitor, Q=121\ nC=121\times 10^{-9}\ C

Let n is the number of excess electrons are on that plate. Using the quantization of charges, the total charge on the negative plate is given by :

Q=ne

e is the charge on electron

n=\dfrac{Q}{e}

n=\dfrac{121\times 10^{-9}}{1.6\times 10^{-19}}

n=7.5625\times 10^{11}

or

n = 756.25 giga electrons

So, there are 756.25 giga electrons are on the plate. Hence, this is the required solution.

6 0
3 years ago
A turn signal lamp must be visible in normal sunlight at a distance of at least ______ feet from the front and rear of the vehic
kaheart [24]

Answer:

500; 300 feet.

Explanation:

A turn signal lamp can be defined as an amber blinking lamp which indicates a driver's intent to change direction. It is extremely important that drivers gives a turn signal (flashing light) on the side toward which he or she is turning either left or right.

Simply stated, the turn signal lamp indicate the driver's intent to turn either leftward or rightward by displaying flashing lights to the front and rear of his or her vehicle.

A turn signal lamp must be visible in normal sunlight at a distance of at least 500 feet from the front and rear of the vehicle if the vehicle is at least 80 inches wide, and at least 300 feet from front and rear of the vehicle if the vehicle is less than 80 inches wide according to the transportation traffics code.

8 0
3 years ago
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