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Firdavs [7]
3 years ago
14

Which descriptions best fit the labels? X: kinetic energy Y: potential energy X: potential energy Y: kinetic energy X: mechanica

l energy Y: electrical energy X: electrical energy Y: mechanical energy
Physics
2 answers:
GalinKa [24]3 years ago
4 0

its the 3rd option!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Alika [10]3 years ago
3 0

Answer:

c.

Explanation:

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Mali loves to make herself dizzy. She spins in place 7 times before falling down right where she was standing. Find her distance
Mila [183]
The answer is 0 bc she didint move
Explanation:
8 0
3 years ago
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As light from a star spreads out and weakens, do gaps form between the photons?
Sati [7]

Answer:

There are no gaps in space between the photons as they travel.

Yes, you can form the shadow of a fire

Explanation:

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2 years ago
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How can a moving coil galvanometer can be made into a dc ammeter?
Dennis_Churaev [7]
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7 0
3 years ago
A pebble is thrown into the air with a velocity of 19/m at an angle of 36 with respect to the horizontal.
kow [346]

Answer:

The maximum height the pebble reaches is approximately;

A. 6.4 m

Explanation:

The question is with regards to projectile motion of an object

The given parameters are;

The initial velocity of the pebble, u = 19 m/s

The angle the projectile path of the pebble makes with the horizontal, θ = 36°

The maximum height of a projectile, h_{max}, is given by the following equation;

h_{max} = \dfrac{\left (u \times sin(\theta) \right)^2}{2 \cdot g}

Therefore, substituting the known values for the pebble, we have;

h_{max} = \dfrac{\left (19 \times sin(36 ^{\circ}) \right)^2}{2 \times 9.8} = 6.3633894140470403035477570509439

Therefore, the maximum height of the pebble projectile, h_{max} ≈ 6.4 m.

3 0
2 years ago
A man throws a ball straight up to his friend on a balcony who catches it at its highest point. The ball was thrown with an init
Ede4ka [16]

Answer:

The maximum height reached by the ball is 16.35 m.

Explanation:

Given;

initial velocity of the ball, u = 17.9 m/s

the final velocity of the ball at the maximum height, v = 0

The maximum height reached by the ball is given by;

v² = u² + 2gh

During upward motion, gravity is negative

v² = u² + 2(-g)h

v² = u² -  2gh

0 = u² -  2gh

2gh = u²

h = u² / 2g

h = (17.9)² / (2 x 9.8)

h = 16.35 m

Ttherefore, the maximum height reached by the ball is 16.35 m.

3 0
2 years ago
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