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Nata [24]
3 years ago
7

If i try to fail and succeed which one did I do

Physics
1 answer:
Novay_Z [31]3 years ago
7 0
You've failed because you failing becomes a statement rather than it becoming fact or what actually happened. 
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The 8.00-cm long second hand on a watch rotates smoothly.
dolphi86 [110]
The watch hand covers an angular displacement of 2π radians in 60 seconds.

ω = 2π/60
ω = 0.1 rad/s

v = ωr
v = 0.1 x 0.08
v = 8 x 10⁻³ m/s
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How is electrical energy produced from potential and kinetic energy?
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The view that time is a scarce resource that must be rationed and controlled through the use of schedules and appointments, and
Diano4ka-milaya [45]

Answer:

Monochronic.

Explanation:

This view is called as Monochronic.

The dictionary definition of Mono-chronic is that  Monochronic people just like to do one thing at a time. They respect a certain uniformity and sense of being a suitable place and time for different activities. They don't esteem interruptions. It has been generally observe that their focus and productivity remains higher than the polychronic.( Those we are comfortable with performing multiple task at a time)

6 0
3 years ago
A 200.0 g block rests on a frictionless, horizontal surface. It is pressed against a horizontal spring with spring constant 4500
kenny6666 [7]

Answer:

 6 m/s

Explanation:

Given that :

mass of the block   m =  200.0 g  = 200 × 10⁻³ kg

the horizontal spring constant   k  =  4500.0 N/m

position of the block (distance x) = 4.00 cm  = 0.04 m

To determine the speed the block will be traveling when it leaves the spring; we applying the  work done on the spring as it is stretched (or compressed) with the kinetic energy.

i.e \frac{1}{2} kx^2  = \frac{1}{2} mv^2

kx^2 = mv^2

4500* 0.04^2 = 200*10^{-3} *v^2

7.2 =200*10^{-3}*v^{2}

v^{2}   =\frac{7.2}{200*10^{-3}}

v   =\sqrt{\frac{7.2}{200*10^{-3}}}

v = 6 m/s

Hence,the speed the block will be traveling when it leaves the spring is  6 m/s

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3 years ago
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i dont think anything will happen so maybe A: the wall is larger than you.

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