In a chemical reaction one or more reactants combine or react to form one or more product(s) with different chemical and physical properties.
When aqueous sodium sulfide reacts with aqueous copper(II) nitrate results in the formation of aqueous sodium nitrate and solid copper(ll) sulfide.
First, identify the chemical symbols for the elements in the compounds.
Sodium sulphide = 
Copper(II) nitrate = 
Sodium nitrate = 
Copper(II) sulfide = 
The chemical reaction is given as:

Now, balance the chemical equation:
For balance the equation, multiply
by 2.
Thus,

Answer:
C₅H₈O₂
Explanation:
methyl methacrylate = 100 amu
6.91g CO₂ = 0.157 moles
2.26g H₂O = 0.125 moles
0.157 ÷ 0.125 = 1.256
{(CO₂)₁.₂₅₆ + (H₂O)₁} × 4 = (CO₂)₅ + (H₂O)₄
C₅H₈O?
C₅ = 60.05 amu H₈ = 8.064 amu
60.05 + 8.064 = 68.114 amu
100 amu - 68.114 amu = 31.886 amu
O = 16 amu
O = 2
Answer:
See explanation
Explanation:
the compound that gives the fastest SN2 reaction with sodium methoxide- 1-bromohexane
the compound that gives the fastest SN1 reaction- 3-bromo-3-methylpentane
the compound(s) that undergo an SN1 reaction to give rearranged products- 1-bromo-2,2-dimethylbutane
the compound that is least reactive to sodium methoxide in methanol -
3-bromo-3-methylpentane
the compound(s) that can exist as diastereomers - 3-bromo-3-methylpentane
the compound(s) that can exist as enantiomers- 3-bromo-2-methylpentane
Answer:
3.09 × 10-27 kg
Explanation:
I also had this question on edge and got it correct