1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alika [10]
2 years ago
7

After combining components of two vectors to be added, it was found that the resultant vector has an x-component of -177 cm and

a y.component of -214 cm
What angle measured counterclockwise from the positive x-axis will properly describe the direction of the resultant vector? (Round to the nearest tenth of a
degree.)
0 219,6
O 50.4
оооо
O 3204
0 230.4
Physics
1 answer:
3241004551 [841]2 years ago
8 0

The angle measured counterclockwise from the positive x-axis is θ = 50.4°

<h3>How to get the angle correspondent to a vector?</h3>

Here we know that the vector is:

V = < -177 cm, -214 cm>

To get the correspondent angle for this vector, we can think that this is the hypotenuse of a right triangle, such that the y-component and x-component are the cathetus.

Then, to get the angle (measured counterclockwise from the positive x-axis) is given by:

Tan(θ) = (opposite cathetus)/(adjacent cathetus)

Tan(θ) = (-214cm)/(-177 cm)

Using the inverse tangent function we get:

Atan(Tan(θ)) = Atan((-214cm)/(-177 cm))

θ = 50.4°

So the angle is 50.4°

If you want to learn more about vectors, you can read:

brainly.com/question/3184914

You might be interested in
Question 1 of 20 :
pochemuha

Answer:

B. Globular clusters    

are scattered throughout the galactic halo that surrounds the Milky Way.

Explanation:

6 0
3 years ago
Read 2 more answers
(10%) Problem 10: A 7.25-kg bowling ball moving at 9.85 m/s collides with a 0.875-kg bowling pin, which is scattered at an angle
siniylev [52]

Answer

given,

mass of bowling ball = 7.25 Kg

moving speed of the bowling ball = 9.85 m/s

mass of bowling in = 0.875 Kg

scattered at an angle = θ = 21.5°

speed after the collision = 10.5 m/s

angle of the bowling ball

tan \theta_1 = \dfrac{-[m_2v_2Sin \theta_2]}{m_1v_1 - (m_2v_2cos \theta_2)}

tan \theta_1 = \dfrac{-[0.875\times 10.5 \times Sin 21.5^0]}{7.25\times 9.85 - (0.875\times 10.5 \times cos 21.5^0)}

tan \theta_1 = \dfrac{-[3.3672]}{62.86}

tan \theta_1 = 0.0536

\theta_1 =-3.066^0

b) magnitude of final velocity

v = \dfrac{-m_2v_2sin\theta_2}{m_1 sin\theta_1}

v = \dfrac{-0.875 \times 10.5 sin21.5^0}{7.25 sin(-3.066^0)}

v = 8.68 m/s

5 0
3 years ago
Which step follows the identification of the problem in the technological design process?
STALIN [3.7K]
The answer is research.

5 0
3 years ago
If a 3.1 kg ring of granite decreases in temperature 17.9C. What is the
steposvetlana [31]
I think it’s C but I’m not sure:/
6 0
3 years ago
A uniform rod rotates in a horizontal plane about a vertical axis through one end. The rod is 3.46 m long, weighs 12.8 N, and ro
Mkey [24]

Answer:

a. Rotational inertia: 5.21kgm²

b. Magnitude of it's angular momentum: 123.32kgm²/s

Explanation:

Length of the rod = 3.46m

Weight of the rod = 12.8 N

Angular velocity of the rod= 226 rev/min

a. Rotational Inertia (I) about its axis

The formula for rotational inertia =

I = (1/12×m×L²) + m × ( L ÷ 2)²

Where L = length of the rod

m = mass of the rod

Mass of the rod is calculated by dividing the weight of the rod with the acceleration due to gravity.

Acceleration due to gravity = 9.81m/s²

Mass of the rod = 12.8N/ 9.81m/s²

Mass of the rod = 1.305kg

Rotational Inertia =

(1/12× 1.305 × 3.46²)+ 1.305 ( 3.46÷2)²

Rotational Inertia =  1.3019115 + 3.9057345

Rotational Inertia = 5.207646kgm²

Approximately = 5.21kgm²

b. The magnitude of the rod's angular momentum about the rotational axis is calculated as

Rotational Inertia about its axis × angular speed of the rod.

Angular speed of the rod is calculated as= (Angular velocity of the rod × 2π)/60

= (226×2π) /60

= 23.67 rad/s

Rotational Inertia = 5.21kgm²

The magnitude of the rod's angular momentum about the rotational axis

= 5.21kgm²× 23.67 rad/s

= 123.3207kgm²/s

Approximately = 123.32kgm²/s

7 0
4 years ago
Other questions:
  • Which of the following is true of salt lakes
    13·2 answers
  • When you kick a ball by a force of 26.3 newtons, what is the magnitude and direction of the force that you experience?
    14·1 answer
  • Please help me with this question ASAP.
    10·1 answer
  • Why is the main reason that attitudes are more often revealed in spoken rather than written language
    9·1 answer
  • The absolute temperature of a sample of monatomic ideal gas is doubled at constant volume. What effect, if any, does this have o
    6·1 answer
  • Half-Life refers to radiation levels<br> true or false
    7·1 answer
  • ? If you are not moving, Newton's First Law says you
    13·2 answers
  • Why is water pollution a concern if water is continuously cycled through Earth’s systems?
    10·1 answer
  • A certain sprinter has a top speed of 11.3 m/s. If the sprinter starts from rest and accelerates at a constant rate, he is able
    11·1 answer
  • Which image shows an object or objects moving with accelerated motion?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!