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Lena [83]
3 years ago
7

Determine the total volume in milliliters of water a chemist should add if they want to prepare an 0.200 M aqueous solution with

30.2 g of NaCI? Assume the density of the resulting solution is the same as the water.
PLEASE WRITE THE EQUATION!!!!
Ill mark brainliest too
Chemistry
2 answers:
olchik [2.2K]3 years ago
8 0

\\ \tt\rightarrowtail Molarity=\dfrac{Mass}{Molar\:mass\times Volume}

\\ \tt\rightarrowtail Volume=\dfrac{Molarity(Molar\:mass)}{Mass}

\\ \tt\rightarrowtail Volume=\dfrac{0.2(58.5)}{30.2}

\\ \tt\rightarrowtail Volume=0.387L

  • Volume=387mL
abruzzese [7]3 years ago
4 0

Answer:

Which of these sentences from the excerpt most strongly supports the correct answer to Question 5?

Answer choices for the above question

Quesiton 5 says

Which of these inferences about the author’s point of view is best supported by the entire excerpt?

From: The Immortal Life of Henrietta Lacks" lesson

A. “She’s simply called HeLa, the code name given to the world’s first immortal human cells—her cells, cut from her cervix just months before she died.”

B. “I’ve spent years staring at that photo, wondering what kind of life she led, what happened to her children, and what she’d think about cells from her cervix living on forever—bought, sold, packaged, and shipped by the trillions to laboratories around the world.”

C. “One scientist estimates that if you could pile all HeLa cells ever grown onto a scale, they’d weigh more than 50 million metric tons—an inconceivable number, given that an individual cell weighs almost nothing.”

D. “All of the stories mentioned that scientists had begun doing research on Henrietta’s children, but the Lackses didn’t seem to know what that research was

Explanation:

Which of these sentences from the excerpt most strongly supports the correct answer to Question 5?

Answer choices for the above question

Quesiton 5 says

Which of these inferences about the author’s point of view is best supported by the entire excerpt?

From: The Immortal Life of Henrietta Lacks" lesson

A. “She’s simply called HeLa, the code name given to the world’s first immortal human cells—her cells, cut from her cervix just months before she died.”

B. “I’ve spent years staring at that photo, wondering what kind of life she led, what happened to her children, and what she’d think about cells from her cervix living on forever—bought, sold, packaged, and shipped by the trillions to laboratories around the world.”

C. “One scientist estimates that if you could pile all HeLa cells ever grown onto a scale, they’d weigh more than 50 million metric tons—an inconceivable number, given that an individual cell weighs almost nothing.”

D. “All of the stories mentioned that scientists had begun doing research on Henrietta’s children, but the Lackses didn’t seem to know what that research was

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ruslelena [56]

Answer:

The initial concentration of ammonia is 0.14 M and the pH of the solution at equivalence point is 5.20

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}      .....(1)

Molarity of HCl solution = 0.164 M

Volume of solution = 23.8 mL = 0.0238 L    (Conversion factor:  1 L = 1000 mL)

Putting values in equation 1, we get:

0.164M=\frac{\text{Moles of HCl}}{0.0238L}\\\\\text{Moles of HCl}=(0.146mol/L\times 0.0238L)=0.0035mol

The chemical equation for the reaction of ammonia and HCl follows:

NH_3+HCl\rightarrow NH_4^++Cl^-

By Stoichiometry of the reaction:

1 mole of HCl reacts with 1 mole of ammonia

So, 0.0035 moles of HCl will react with = \frac{1}{1}\times 0.0035=0.0035mol of ammonia

  • Calculating the initial concentration of ammonia by using equation 1:

Moles of ammonia = 0.0035 moles

Volume of solution = 25 mL = 0.025 L

Putting values in equation 1, we get:

\text{Initial concentration of ammonia}=\frac{0.0035mol}{0.025L}=0.14M

By Stoichiometry of the reaction:

1 mole of ammonia produces 1 mole of ammonium ion

So, 0.0035 moles of ammonia will react with = \frac{1}{1}\times 0.0035=0.0035mol of ammonium ion

  • Calculating the concentration of ammonium ion by using equation 1:

Moles of ammonium ion = 0.0035 moles

Volume of solution = [23.8 + 25] mL = 48.8 mL = 0.0488 L

Putting values in equation 1, we get:

\text{Molarity of ammonium ion}=\frac{0.0035mol}{0.0488L}=0.072M

  • To calculate the acid dissociation constant for the given base dissociation constant, we use the equation:

K_w=K_b\times K_a

where,

K_w = Ionic product of water = 10^{-14}

K_a = Acid dissociation constant

K_b = Base dissociation constant = 1.8\times 10^{-5}

10^{-14}=1.8\times 10^{-5}\times K_a\\\\K_a=\frac{10^{-14}}{1.8\times 10^{-5}}=5.55\times 10^{-10}

The chemical equation for the dissociation of ammonium ion follows:

NH_4^+\rightarrow NH_3+H^+

The expression of K_a for above equation follows:

K_a=\frac{[NH_3][H^+]}{[NH_4^+]}

We know that:

[NH_3]=[H^+]=x

[NH_4^+]=0.072M

Putting values in above expression, we get:

5.55\times 10^{-10}=\frac{x\times x}{0.072}\\\\x=6.32\times 10^{-6}M

To calculate the pH concentration, we use the equation:

pH=-\log[H^+]

We are given:

[H^+]=6.32\times 10^{--6}M

pH=-\log (6.32\times 10^{-6})\\\\pH=5.20

Hence, the initial concentration of ammonia is 0.14 M and the pH of the solution at equivalence point is 5.20

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As per the rule, oxidation number of alkaline earth metals in their compounds is +2. Oxidation number of oxygen in it's compounds is -2(except peroxides) and the sum of oxidation numbers of all the elements of a neutral compound is zero.
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Concentrated sulfuric acid (18.3 M) has a density of 1.84 g/mL.
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<h3>What is concentration?</h3>
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  • Mass concentration, molar concentration, number concentration, and volume concentration are four different categories of mathematical description.  
  • Any type of chemical mixture can be referred to by the term "concentration," however solutes and solvents in solutions are most usually mentioned.
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<h3>How is concentration determined?</h3>
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