<h3>16.</h3>
Your answer is correct.
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<h3>17.</h3>
The fractional change in resistance is equal to the given temperature coefficient multiplied by the change in temperature.
R = R₀×(1 + α×ΔT)
R = (10.0 Ω)×(1 + 0.004×(65 -20)) = 11.8 Ω
Kinetic energy is equal to half of an objects mass multiplied by the velocity squared.
T<span>he relationship between wavelength and frequency is inverse.
This is as the wavelength increases the frequency decreases and as the wavelength decreases the frequency increases.
The light meets this equation that reflects the relationship between wavelength and frequency:
c = wavelength * frequency => wavelength = c / frequency
where c is the constant speed of light.
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Answer:
The transverse displacement is
Explanation:
From the question we are told that
The generally equation for the mechanical wave is

The speed of the transverse wave is 
The amplitude of the transverse wave is 
The wavelength of the transverse wave is 
At t= 0.150s , x = 1.51 m
The angular frequency of the wave is mathematically represented as

Substituting values


The propagation constant k is mathematically represented as

Substituting values


Substituting values into the equation for mechanical waves

Answer:
Hypothesis:
The amount of limestone that dissolves in the acid is directly proportional to the concentration of acid used.
Explanation:
Acids dissolve limestone according to the following general equation;
2HX(aq) + CaCO3(s) -------> CaX2(aq) + H2O (l) + CO2(g). Where HX represents any acid at all.
This dissolution process is a chemical reaction. It was experimentally observed that the amount of limestone that dissolved in acid depends on the concentration of acid. Various concentrations of acid were then prepared and a particular mass of limestone was dissolved in each concentration of acid. The amount of limestone dissolved in each case was carefully noted.
It was observed that as the concentration of acid increased, the amount of limestone dissolved increased also and vice versa, hence the hypothesis proposed above.