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3 years ago

Can someone help me in that plz ??!

Physics

1 answer:

olga_2 [115]3 years ago

8 0

Answer: These forces are an example of newtons third law every action has equal and opposite reaction

Explanation:UwU

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Un recipiente con una capacidad de 25L contiene un gas a una presión de 7,5 atm. Calcula la nueva presión a la que se verá somet

amid [387]

Responder:

18.75 atmósferas

Explicación:

Paso uno:

datos dados

volumen inicial V1 = 25L

Presión inicial P1 = 7.5 atm

volumen final V2 = 10L

presión final P2 = ??

Segundo paso:

Aplicando la expresión de gas que relaciona el volumen y la presión, es decir

P1V1 = P2V2

sustituyendo nuestros datos tenemos

7.5 * 25 = P2 * 10

187.5 = P2 * 10

divide ambos lados por 10

P2 = 187.5 / 10

P2 = 18.75 atmósferas

La presión final es de 18.75 atm.

5 0

3 years ago

A 400 N steel ball is suspended by a light rope from the ceiling. The tension in the rope is

alina1380 [7]

Answer:

As force = tension in string so tension in string is 400N

Explanation:

8 0

3 years ago

HELP ASAP!!!!!!! PLEASE WILL GIVE BRAINLIEST

Pani-rosa [81]

Answer:

The three major parts of a cell are:

a. Cell membrane

b. Nucleus

c. Cytoplasm

Explanation:

a. Cell membrane:

It provides protection for a cell.

b. Nucleus:

It controls and regulates the activities of cell.

c. Cytoplasm:

It supports and suspends organelles and cellular molecules.

8 0

3 years ago

Read 2 more answers

A speaker generates a continuous tone of 440 Hz. In the drawing, sound travels into a tube that splits into two segments, one lo

chubhunter [2.5K]

Answer:

The minimum difference between the lengths of the two tubes should be 0.385 meters.

Explanation:

As we known that for any two waves to arrive in phase at any point the difference in the path traveled by the waves should be an integral multiple of the wavelength of the wave.

Mathematically we can write:

$\Delta x=n\frac{\lambda }{2}$

For the given wave we have

$\lambda =\frac{v}{\nu }$

Applying values we get

$\lambda =\frac{339}{440 }=0.77m$

Thus the minimum difference in the lengths of the tubes can be obtained by putting the value of n = 1

$\therefore \Delta x=1\times \frac{0.77}{2}=0.385m$

7 0

4 years ago

A gold wire has a cross-sectional area of 1.0 cm^2 and a resistivity of 2.8 × 10^-8 Ω ∙ m at 20°C. How long would it have to be

Karo-lina-s [1.5K]

Answer:

Length, l = 3.57 meters

Explanation:

It is given that,

Area of cross-section of gold wire, $A=1\ cm^2=0.0001\ m^2$

Resistivity of gold wire, $\rho=2.8\times 10^{-8}\ \Omega-m$

Resistance, R = 0.001 ohms

Resistance in terms of length and area is given by :

$R=\rho \dfrac{l}{A}$

$l=\dfrac{RA}{\rho}$

$l=\dfrac{0.001\times 0.0001}{2.8\times 10^{-8}}$

l = 3.57 meters

So, the length of the wire is 3.57 meters. Hence, this is the required solution.

4 0

3 years ago