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Margaret [11]
3 years ago
8

Which of the following is a TRUE statement about the current space station?

Chemistry
2 answers:
Alex73 [517]3 years ago
6 0

it is an international project between several countries?

svlad2 [7]3 years ago
4 0
I believe that it is C.
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What are various ways in which elements are classified?
balu736 [363]
They are classified by similar properties and number of valence electrons and energy levels
3 0
3 years ago
What is the percentage of water in the hydrate CoCl2 • 6H2O? Show your work.
Lelu [443]
Hello!

First you have to find the molar mass of the molecules

C = 12
O = 16
2Cl = 71
6H2O = 108

Add them up to find the total molar mass

12 + 16 + 71 + 108 = 207g/mol

Divide the amount of water by the total molar mass

108 / 207 = 0.5217

Convert this to a decimal

0.5217 = 52.17%

The answer is 52.17%

Hope this helps!
7 0
4 years ago
Will the composition of water molecules vary depending on their source?
Alecsey [184]

Answer:

It does not matter where the sample of water came from or how it was prepared. Its composition, like that of every other compound, is fixed.

6 0
3 years ago
A chemical reaction can theoretically produce 137.5 grams of product, but it actually produced 112.9 grams. Which is the percent
Serhud [2]

Answer:

Explanation:

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3 0
3 years ago
Read 2 more answers
Considering the following precipitation reaction: Pb(NO3)2(aq) + 2KI(aq) → PbI2(s) + 2KNO3(aq) Which ion would NOT be present in
Allisa [31]

Answer:

The question is incomplete and confusing.

  • In the complete ionic equation you write all the ions that are formed. Those are: Pb²⁺, NO₃⁻, K⁺, and I⁻. They all are present in the complete ionic equation.

  • In the net ionic equation, the spectator ions do not appear. They are: NO₃⁻ and K⁺. They would not be present in the net ionic equation, but they do in the complete ionic equation.

See below the details.

Explanation:

Which compound will not form ions?

<u />

<u>1. Write the balanced molecular equation:</u>

  • Pb(NO₃)₂(aq) + 2KI(aq) → PbI₂(s) + 2KNO₃(aq)

<u />

<u>2. Write the ionizations for the ionic aqueous compounds:</u>

<u />

  • Pb(NO₃)₂(aq) →  Pb⁺²(aq) + 2NO₃⁻(aq)

  • 2KI(aq) → 2K⁺(aq) + 2I⁻(aq)

  • 2KNO₃(aq) → 2K⁺(aq) + 2NO₃⁻(aq)

<u />

<u>3. Write the complete ionic equation:</u>

Pb⁺²(aq) + 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) → PbI₂(s) +  2K⁺(aq) + 2NO₃⁻(aq)

Hence, since PbI₂(s) does not ionize, but stays in solid form, it will not form ions.

All, Pb⁺², NO₃⁻, K⁺, and I⁻ will be present in the total ionic equation.

It is in the net ionic equation that the spectator ions are removed. Those, are NO₃⁻ and K⁺, because they are on both sides of the complete ionic equation.

3 0
3 years ago
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