Answer:
The new temperature will be 2546 K or 2273 °C
Explanation:
Step 1: Data given
The initial temperature = 1000 °C =1273 K
The volume = 20L
The volume increases to 40 L
Step 2: Calculate the new temperature
V1/T1 = V2/T2
⇒with V1 = the initial volume = 20L
⇒with T1 = the initial temperature = 1273 K
⇒with V2 = the increased volume = 40L
⇒with T2 = the new temperature = TO BE DETERMINED
20L/ 1273 K = 40L / T2
T2 = 40L / (20L/1273K)
T2 = 2546 K
The new temperature will be 2546 K
This is 2546-273 = 2273 °C
Since the volume is doubled, the temperature is doubled as well
Answer:
a ) 1876.14 grams CaBr2
b ) 19.78 grams N2
sorry..i only have time to do the first two :)
Explanation:
Answer:
1.15
Explanation:
2SO₂ + O₂ ⟶ 2SO₃; K =1.32
SO₂ + ½O₂ ⟶ SO₃; K₁ = ?
When you divide an equation by 2, you take the square root of its equilibrium constant.
K₁ = √1.32 = 1.15
The equilibrium constant is 1.15.
The answer is A. Mom carefully bandaged my finger.
A). 4
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