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klio [65]
2 years ago
12

50+50 easy points and have a good rest of your day! :)

Mathematics
2 answers:
Scorpion4ik [409]2 years ago
7 0
100
Have a good day! :)
HACTEHA [7]2 years ago
7 0

Answer:

50 + 50 = 100

Step-by-step explanation: Also I hope you have an amazing day/night!!!

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Which is the graph of y= 3/4x-3?<br>Graph C<br>Graph B<br>Graph A<br><br><br><br>​
Brilliant_brown [7]
Graph A because the slope and y intercept is correct on that graph
4 0
2 years ago
Evaluate the expression for the given value of x.<br> 6x + 7 for x = 2<br> The solution is
pav-90 [236]

Answer:

6x + 7

6 * 2

12 + 7

=19

Step-by-step explanation:

4 0
3 years ago
I really need help please.
love history [14]

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64

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6 0
3 years ago
The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f
WITCHER [35]

Answer:

Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle

r=12\ cm\\b=12\ cm\\h=12\ cm

substitute

A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2

simplify

Factor 36

A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r

substitute the given values

C=\frac{1}{2}\pi (12)\\C=6\pi\ cm

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm

simplify

AC=12\sqrt{2}\ cm

Find the perimeter

P=(6\pi+12\sqrt{2})\ cm

simplify

Factor 6

P=6(\pi+2\sqrt{2})\ cm

4 0
3 years ago
Answer and shown work for 5x + y = 10 -x - y = -2
konstantin123 [22]
Solve first equation for y: 
5x+y=10
y=10-5x. Plug this equation into second equation

-x-(10-5x)=-2
-x-10+5x=-2
4x=8
x=2 (plug x into first equation)

5(2)+y=10
y=0
4 0
3 years ago
Read 2 more answers
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