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Alisiya [41]
4 years ago
11

A particle moving in the x direction is being acted upon by a net force F(x)=Cx2, for some constant C. The particle moves from x

i=L to xf=3L. What is ΔK, the change in kinetic energy of the particle during that time?
Physics
1 answer:
elixir [45]4 years ago
5 0

Answer:

Change in kinetic energy is ( 26CL³)/3

Explanation:

Given :

Net force applied, F(x) = Cx²  ....(1)

Displacement of the particle from xi = L to xf = 3L.

The work-energy theorem states that change in kinetic energy of the particle is equal to the net amount of work is done to displace the particle.

That is,

ΔK = W = ∫F·dx

Substitute equation (1) in the above equation.

ΔK =  ∫Cx²dx

The limit of integration from xi = L to xf = 3L, so

\Delta K=\frac{C}{3}(x_{f} ^{3} - x_{i} ^{3})

Substitute the values of xi and xf in the above equation.

\Delta K=\frac{C}{3}((3L) ^{3} - L ^{3})

\Delta K=\frac{C}{3}\times26L^{3}

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The answer is definitely A. A transparent material is a material that allows light to pass through it and can be seen through. A glass jar can be seen through. Some people might say B, which is a mirror, but a mirror cannot be seen through, it only shows reflection. Hope i helped. Have a nice day and Happy New Year.
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What is the wavelength of an earthquake wave if it has a speed of 4 km/s and a frequency of 7 Hz?
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4 years ago
Plzzzz urgent <br><br><br>solve this​
Mariana [72]

Answer:

\large{ \tt{☄ \: EXPLANATION}} :

  • Before solving , You'll have to know - When an object starts from the state of rest , in this case , initial velocity ( u ) = 0

  • Notice that we're provided the time ( t ) in minutes. So , first thing we have to do is convert the minutes into seconds. It would be - Time ( t ) = 5 minutes = 5 × 60 sec = 300 sec [ 1 min = 60 sec ]

  • Here , We're provided - Initial velocity ( u ) = 0 , Final velocity ( v ) = 60 m / s , Time taken ( t ) = 300 seconds & We're asked to find out the acceleration ( a ) & distance covered by the jeep ( s ) .

\large{ \tt{♨ \:LET'S \: START}} :

  • Acceleration is defined as the rate of change of velocity. We know :

\large{ \boxed{ \tt{❁ \: ACCELERATION \: (a) =  \frac{FINAL \: VELOCITY(v) - INITIAL \: VELOCITY(u)}{TIME \: TAKEN \: ( \: t \: )}}}}

- Plug the values & then simplify !

\large{ \bf{↬a =  \frac{60 - 0}{300}  =  \frac{60}{300} =  \boxed{ \bold{ \bf{0.2 \: m {s}^{ - 2} }}} }}

  • The acceleration of the jeep is 0.2 m/s²

\large{ \tt{۵ \: AGAIN, \: USING\: SECOND \: EQUATION \: OF \: MOTION}} :

\boxed{ \large{ \bf{✾ \: s =  \frac{u + v}{2}  \times t}}}

- Plug the values & then simplify !

\large{ \bf{↦s =  \frac{0 + 60}{2}  \times 300 =  \boxed{ \bold{ \bf{9000 \: m}}}}}

  • The distance covered by the jeep is 9000 m .

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7 0
3 years ago
Identify the following physical quantities as scalars or vectors.
34kurt
Position displacement velocity acceleration are vectors and the rest are scalars
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19) A child on a sled starts from rest at the top of a 15.0° slope. If the trip to the bottom takes 15.2 s,
sveticcg [70]

Answer: 288.8 m

Explanation:

We have the following data:

t=15.2 s is the time it takes to the child to reach the bottom of the slope

V_{o}=0 is the initial velocity (the child started from rest)

\theta=15\° is the angle of the slope

d is the length of the slope

Now, the Force exerted on the sled along the ramp is:

F=ma (1)

Where m is the mass of the sled and a its acceleration

In addition, if we draw a free body diagram of this sled, the force along the ramp will be:

F=mg sin \theta (2)

Where g=9.8 m/s^{2} is the acceleration due gravity

Then:

ma=mg sin \theta (3)

Finding a:

a=g sin \theta (4)

a=9.8 m/s^{2} sin(15\°) (5)

a=2.5 m/s^{2} (6)

Now, we will use the following kinematic equations to find d:

V=V_{o}+at (7)

V^{2}=V_{o}^{2}+2ad (8)

Where V is the final velocity

Finding V from (7):

V=at=(2.5 m/s^{2})(15.2 s) (9)

V=38 m/s (10)

Substituting (10) in (8):

(38 m/s)^{2}=2(2.5 m/s^{2})d (11)

Finding d:

d=288.8 m

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