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Angelina_Jolie [31]
2 years ago
6

Altitude refers to ________________. Group of answer choices the angular distance from the celestial equator the angular height

of Polaris above or below the horizon the number of meters you're standing at from sea level the angular height away from the horizon
Physics
1 answer:
liraira [26]2 years ago
3 0

In Science, altitude refers to: D. the angular height away from the horizon.

<h3>What is altitude?</h3>

Altitude is also referred to as an elevation and it can be defined as the vertical distance (height) above a natural satellite or the surface of a planet such as land or sea level.

This ultimately implies that, an altitude is vertical height (elevation) of an object or physical body above a particular location or planetary reference plane such as land or sea level on Earth.

In conclusion, altitude is the angular height of an object or physical body away from the horizon.

Read more on altitude here: brainly.com/question/1159693

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When an object is lifted 12 meters off the ground, it gains a certain amount of potential energy. If the same object is lifted 2
alexandr402 [8]
I think the answer is twice as much
8 0
1 year ago
Current is the movement of negative charges called protons.<br> A. True<br> B. False
Kruka [31]

Answer: Option B) False

Explanation:

Current is the movement of negative charges called electrons. Protons, neutrons and electrons are the three subatomic particles that make up particles of the conductors that transmit current, however electrons are negatively charged and their gain or loss determines movement of electric current.

Thus, the statement is false

5 0
2 years ago
Help! I don’t really know what it’s asking
Misha Larkins [42]
You have to do the math of each and see which one adds up to 66.5
6 0
2 years ago
A projectile is launched at an angle above the
gtnhenbr [62]
The first rule of vectors is that the horizontal and vertical components are separate. Disregarding air resistance, the only thing we have to worry about is gravity.

The appropriate suvat to use for the vertical component is v = u +at
I will take a to be -9.81, you may have to change it to be 10 if your qualification likes g to be 10.

v = 30 + (-9.81x2)
v = 30 - 19.62
=10.38m/s

Therefore we know that after 2.0 s the vertical component will be 10.38ms^-1, ie 10m/s as the answers given are all to 2sf.

The horizontal component is completely separate to the vertical component and since there is no air resistance, it will remain constant throughout the projectiles trajectory. Therefore it will remain at 40ms^-1.

Combining this together we get:
(1) vx=40m/s and vy=10m/s

7 0
2 years ago
In this problem, you will practice applying this formula to several situations involving angular acceleration. In all of these s
riadik2000 [5.3K]

Answer:

Part a)

\alpha = \frac{2(m_1 - m_2)g}{(m_1 + m_2)L}

Part b)

\alpha = \frac{6(m1 - m_2)g}{3(m_1 + m_2)L + m_{bar}L}

Explanation:

As we know that the see saw bar is massless so here torque due to two masses is given as

\tau = I\alpha

here we will have

\tau = (m_1g - m_2g)(\frac{L}{2})

now we will have inertia of two masses given as

I = (m_1 + m_2)(\frac{L}{2})^2

now we have

I = (m_1 + m_2)\frac{L^2}{4}

now the angular acceleration is given as

\alpha = \frac{\tau}{I}

so we have

\alpha = \frac{2(m_1 - m_2)g}{(m_1 + m_2)L}

Part b)

Now if the rod is not massles then we will have total inertia given as

I = (m_1 + m_2)(\frac{L}{2})^2 + \frac{m_{bar}L^2}{12}

so we will have

I = (m_1 + m_2)\frac{L^2}{4} + \frac{m_{bar}L^2}{12}

now the acceleration is given as

\alpha = \frac{\tau}{I}

\alpha = \frac{6(m1 - m_2)g}{3(m_1 + m_2)L + m_{bar}L}

7 0
3 years ago
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