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dalvyx [7]
3 years ago
5

Name two luminous objects other than the sun

Chemistry
2 answers:
Leto [7]3 years ago
7 0
Laser, Stars, torch, flame in lamp, tube light and electric bulb
jekas [21]3 years ago
3 0

Answer: flame in a lamp, tube light, electric bulb

Explanation:

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HNO3 and H2CO3 are examples of ?
Basile [38]
A) acids because they start with h
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3 years ago
If I have 5.275 moles of gas at a temperature of 575 K and a pressure of 7.75 atmospheres, what is the volume of the gas?
elena55 [62]

Answer:

hi

Explanation:

4 0
3 years ago
Draw the Lewis structure (including all lone pair electrons) for one isomer of the molecular formula C3H8O.
Andreyy89

Answer:

Here's how I would do it.

Explanation:

A Lewis structure shows the valence electrons surrounding the atoms.

1. Identify the central atoms

The central atoms are the least electronegative atoms (C).

I chose as my central atoms a chain of four C atoms: C-C-C-C

I stuck the most electronegative atom (O) at the end of the chain:

C-C-C-C-O

2. Complete the structure

The hydrogen atoms must be terminal. Add enough to give every atom an octet.

You should get a structure like the one below

3 0
3 years ago
A student is asked to standardize a solution of potassium hydroxide. He weighs out 1.08 g potassium hydrogen phthalate (KHC8H4O4
natka813 [3]

Answer:

A. 0.143 M

B. 0.0523 M

Explanation:

A.

Let's consider the neutralization reaction between potassium hydroxide and potassium hydrogen phthalate (KHP).

KOH + KHC₈H₄O₄ → H₂O + K₂C₈H₄O₄

The molar mass of KHP is 204.22 g/mol. The moles corresponding to 1.08 g are:

1.08 g × (1 mol/204.22 g) = 5.28 × 10⁻³ mol

The molar ratio of KOH to KHC₈H₄O₄ is 1:1. The reacting moles of KOH are 5.28 × 10⁻³ moles.

5.28 × 10⁻³ moles of KOH occupy a volume of 36.8 mL. The molarity of the KOH solution is:

M = 5.28 × 10⁻³ mol / 0.0368 L = 0.143 M

B.

Let's consider the neutralization of potassium hydroxide and perchloric acid.

KOH + HClO₄ → KClO₄ + H₂O

When the molar ratio of acid (A) to base (B) is 1:1, we can use the following expression.

M_{A} \times V_{A} = M_{B} \times V_{B}\\M_{A} = \frac{M_{B} \times V_{B}}{V_{A}} \\M_{A} = \frac{0.143 M \times 10.1mL}{27.6mL}\\M_{A} =0.0523 M

8 0
3 years ago
How do chemists change hydrocarbons into other compounds
zlopas [31]
The structures and chemistry of individual hydrocarbons depend a large part on the types of chemical bonds that link together the atoms of their constituent molecules. Hydrocarbons are derived by chemical degradation.
4 0
3 years ago
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