A day is added to February every four tears as a corrective measure. The Earth does not exactly revolve around the sun for 365 days. There is a small offset that is corrected by adding a day to February. This happens every four years and it is called Leap year.
Answer:
ExplanationIt is moving from 4s to 8s at a constant speed of 4 cm:
Answer:
The new partial pressures after equilibrium is reestablished for 
:
The new partial pressures after equilibrium is reestablished 
:
The new partial pressures after equilibrium is reestablished for 
:
Explanation:
At equilibrium before adding chlorine gas:
Partial pressure of the 
Partial pressure of the 
Partial pressure of the 
The expression of an equilibrium constant is given by :
At equilibrium after adding chlorine gas:
Partial pressure of the 
Partial pressure of the 
Partial pressure of the 
Total pressure of the system = P = 263.0 Torr
At initail
(13.2) Torr (32.8) Torr (13.2) Torr
At equilbriumm
(13.2-x) Torr (32.8-x) Torr (217.0+x) Torr
Solving for x;
x = 6.402 Torr
The new partial pressures after equilibrium is reestablished for :
The new partial pressures after equilibrium is reestablished :
The new partial pressures after equilibrium is reestablished for :
Answer:
Total numbe of protons and neutrons in a single atom of that element
Explanation:
Hello,
I'll answer the question by filling in the blank spaces
"The atomic mass of an element is equal to the total number of proton and neutron in a particular atom of the element. The atomic mass of an element is equal to the atomic weight. Its mass number one-twelfth of the mass of carbon-12 atom a weighted mass of all naturally occurring isotopes of the elements. Its atomic mass is the average mass of all the naturally occurring isotopes of the element."
The atomic mass of an element is the total number of protons and neutrons in a single atom of that element.
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Answer:</h3>
A. 1.4 V
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Explanation:</h3>
We are given the half reactions;
Ni²⁺(aq) + 2e → Ni(s)
Al(s) → Al³⁺(aq) + 3e
We are required to determine the cell potential of an electrochemical cell with the above half-reactions.
E°cell = E(red) - E(ox)
From the above reaction;
Ni²⁺ underwent reduction(gain of electrons) to form Ni
Al on the other hand underwent oxidation (loss of electrons) to form Al³⁺
The E.m.f of Ni/Ni²⁺ is -0.25 V and that of Al/Al³⁺ is -1.66 V
Therefore;
E°cell = -0.25 V - (-1.66 V)
= -0.250V + 1.66 V
= + 1.41 V
= + 1.4 V
Therefore, the cell potential will be +1.4 V
