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pochemuha
3 years ago
15

Propose a mechanism to account for the formation of a cyclic acetal from 4-hydroxypentanal and one equivalent of methanol. If th

e carbonyl oxygen of 4-hydroxypentanal is enriched with oxygen-18, do you predict that the oxygen label appears in the cyclic acetal or in the water

Chemistry
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

If carbonyl oxygen of 4-hydroxypentanal is enriched with O^{18}, then the oxygen label appears in the water .

Explanation:

  • In the first step, -OH group at C-4 gives intramolecular nucleophilic addition reaction at carbonyl center to produce a cyclic hemiacetal.
  • Then, one equivalent of methanol gives nucleophilic substitiution reaction by substituting -OH group in cyclic hemiacetal to produce cyclic acetal.
  • If carbonyl oxygen of 4-hydroxypentanal is enriched with O^{18}, then the oxygen label appears in the water produced at the end of reaction.
  • Full reaction mechanism has been shown below.

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Please and thank you
Virty [35]

3.8mL of 0.42 phosphoric acid is required.

Reaction

2H3PO4 + 3CaCL3 → Ca3(PO)4 + 6HCl

moles CaCl2 =0.16 mol/L x0.010 L = 0.0016 mol

moles of H3Po4

= 0.0016mol of CaCl2 x 2 mole of H3PO4/3mole of CaCl2

= 0.00106 mol

V of H3PO4 = 0.0016/0.42 = 0.0038L = 3.8mL

V of H3PO4=3.8mL

To know more about calculation in milliliters refer to:-

brainly.com/question/23276655

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4 0
2 years ago
A charged particle is known as a(n) ______.
lubasha [3.4K]

Answer:

electric charge

Explanation:

6 0
2 years ago
How much work is required to lift a 0.500 kg block 18.5 m?
kipiarov [429]

Answer:

Work = 90.65 j

Explanation:

Given data:

Mass = 0.500 Kg

Distance = 18.5 m

Work done = ?

Solution:

Work = force . distance

Force = mg

Work = mg.distance

Work = mgh

Work = 0.500 Kg × 9.8 m/s²× 18.5 m

Work = 90.65 Kg .m²/s²

Kg .m²/s² = j

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3 0
3 years ago
How many moles of mgs2o3 are in 193 g of the compound?
Mashutka [201]

Answer:

             1.414 Moles

Solution:

Data Given:

                 Mass of MgS₂O₃  =  193 g

                 M.Mass of MgS₂O₃  =  136.43 g.mol⁻¹

                 Moles  =  ?

Formula Used:

                            Moles  =  Mass ÷ M.Mass

Putting values,

                            Moles  =  193 g ÷ 136.43 g.mol⁻¹

                            Moles =  1.414 mol

8 0
3 years ago
Please help!!!!
Tomtit [17]

Answer 1) Option D : Discrete


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Answer 2) Option D : The entertainment industry


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6 0
3 years ago
Read 2 more answers
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