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scoray [572]
3 years ago
11

The angle a vector makes with the x-axis of a coordinate system must be what size in order to make one or more of its components

negative?
Physics
2 answers:
Ostrovityanka [42]3 years ago
5 0
The 1st quadrant (0-90 degrees) is the only quadrant where none of the components are negative, so that means that any angle larger than 90 degrees will result in one of the components being negative.
Verdich [7]3 years ago
3 0

Answer:

Angle must be greater than 90 to make one or more components of a vector negative.

Explanation:

There are four ranges of angle given below:

(i) For 0 < θ < 90, both components are positive.

(ii) For 90 < θ < 180, x-component is negative while y-component is positive.

(iii) For 180 < θ < 270, both components are negative.

(iv) For 270 < θ < 360, x-component is positive while y-component is negative.

Hence, angle must be greater than 90 to make one or more components of a vector negative.

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Answer:

a_{cm}=\frac{F}{2M}\\\\F_{fr}=\frac{F}{2}

Explanation:

Given the mass as M, the rotational inertia of the mower is;

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v_{cm}=wR, a_{cm}=\alpha R

\sum F_x=Ma_x, -F+F_{fr}=-Ma_{cm}\\\\a_{cm}=\frac{F-Fr}{M}    \ \ \ \ \ \ \ \ eqtn1\\\\\sum \tau_{cm}=I_{cm}\alpha, F_{fr}(R)}=(MR^2)(\frac{a_{cm}}{R}), ->F_{fr}=Ma_c_m\ \ \  \ \ \ \ eqtn2\\\\a_{cm}=\frac{F-Ma_{cm}}{M}, ->F=2Ma_{cm}\\\\a_{cm}=\frac{F}{2M}\\\\\\\therefore F_{fr}=M(\frac{F}{2M})\\\\F_{fr}=\frac{F}{2}

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A wave has a speed of 30 m/s, a frequency of 6 Hz, and a wavelength of 5 m. If the wavelength remains constant, and the frequenc
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Answer: 60m/s

Explanation:

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In the first case:

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In the second case:

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Wavespeed = 12 Hz x 5m

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Therefore, when frequency is doubled, the speed is also doubled. Thus, the new speed of the wave is 60m/s

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