At a point on the streamline, Bernoulli's equation is
p/ρ + v²/(2g) = constant
where
p = pressure
v = velocity
ρ = density of air, 0.075 lb/ft³ (standard conditions)
g = 32 ft/s²
Point 1:
p₁ = 2.0 lb/in² = 2*144 = 288 lb/ft²
v₁ = 150 ft/s
Point 2 (stagnation):
At the stagnation point, the velocity is zero.
The density remains constant.
Let p₂ = pressure at the stagnation point.
Then,
p₂ = ρ(p₁/ρ + v₁²/(2g))
p₂ = (288 lb/ft²) + [(0.075 lb/ft³)*(150 ft/s)²]/[2*(32 ft/s²)
= 314.37 lb/ft²
= 314.37/144 = 2.18 lb/in²
Answer: 2.2 psi
The specific heat of aluminum is actually simply a
diversion. Because we can directly compute for the specific heat of copper
using the formula:
ΔH = m C ΔT
where ΔH is change in enthalpy or heat lost, m is mass, C
is specific heat and ΔT is change in temp
4,600 J = 150 g * C * (100 °C - 20°C)
C = 0.38 J/g°C
<h2>Answer :</h2><h2 />
Work is the amount of energy transferred. As per the formula
Work = Force x Distance [moved toward the direction of the force]
So as per the formula
<u>Solution : </u>
Force = 825 N
Distance = 35 m
Work = 825 (n) x 35 (m)
Work = 28875 Joules
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