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Jet001 [13]
3 years ago
7

What is the formula for voltage​

Physics
1 answer:
vladimir2022 [97]3 years ago
3 0
U = P / I
U is voltage in Volt
P is power in Watt
I is electric current in Ampère
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A doctor uses an instrument(s) that emits light and allows the doctor to view the inside of a patient’s intestine. What is the d
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The doctor is using fiber optics.
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A shopper is pushing a cart down a grocery store aisle. Starting from rest, the shopper applies a constant force to the cart for
inysia [295]

A shopping cart that starts from rest, is accelerated for 4 s, moves at constant velocity for 4 s, and is decelerated for 4s until returning to rest, has an average acceleration of 0 m/s².

A shopper is pushing a cart down a grocery store aisle. The movement of the cart is:

  • It starts from rest.
  • From t = 0 s to t = 4.0 s it is accelerated with a constant force.
  • From t = 4 s to t = 8.0 s it receives just enough force to balance the friction on the cart.
  • From t = 8 s to t = 12 s it is decelerated until it comes to rest.

All in all, at the initial time (t = 0 s), the velocity is 0 m/s (rest) and at the final time (t = 12 s) the velocity is 0 m/s as well (rest). The average acceleration in that period is:

a = \frac{v_{12}-v__o}{t_{12}-t_0} = \frac{0m/m-0m/s}{12s-0s}  = 0 m/s^{2}

A shopping cart that starts from rest, is accelerated for 4 s, moves at constant velocity for 4 s, and is decelerated for 4s until returning to rest, has an average acceleration of 0 m/s².

Learn more: brainly.com/question/16274121

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3 years ago
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Two students were climbing stairs at school. Student 1 has a weight of 700 N. Student 2 has a weight of 650 N. How much power wo
KIM [24]

Student 1 would have a power 467 W and student 2 would have a power of 433 W. The correct option is the fourth option - Student 1 would have 467 W, and Student 2 would have 433 W of power.

From the question,

We are to calculate the power each student would have to climb the flight of stairs.

Power can be calculated using the formula

P = \frac{F \times d}{t}

Where

P is Power

F is the force

d is the distance

and t is the time

NOTE: The weight of the students represent the force

  • For student 1

F = 700 N

d = 4 m

t = 6 s

∴ P = \frac{700 \times 4}{6}

P = 467 W

  • For student 2

F = 650 N

d = 4 m

t = 6 s

∴ P = \frac{650 \times 4}{6}

P = 433 W

Hence, Student 1 would have a power 467 W and student 2 would have a power of 433 W. The correct option is the fourth option - Student 1 would have 467 W, and Student 2 would have 433 W of power.

Learn more here: brainly.com/question/18801566

3 0
3 years ago
Calculate the energy released by the electron-capture decay of 5727Co. Consider only the energy of the nuclei (ignore the energy
erma4kov [3.2K]

Answer:

Explanation:

⁵⁷Co₂₇  + e⁻¹  =  ²⁷Fe₂₆

mass defect = 56.936296 + .00055 - 56.935399

= .001447 u

equivalent energy

= 931.5 x .001447 MeV

= 1.3479 MeV .

= 1.35 MeV

energy of gamma ray photons = .14  + .017

= .157 MeV .

Rest of the energy goes to neutrino .

energy going to neutrino .

= 1.35 - .157

= 1.193 MeV.

5 0
3 years ago
2. What is stroboscopic motion? -​
Oduvanchick [21]

Answer: The illusion of motion that occurs when a stationary object is first seen briefly in one location and, following a short interval, is seen in another location.

Explanation:

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4 years ago
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