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kenny6666 [7]
3 years ago
15

Will mark branliest. Calculating percent yield: For the reaction Cu + 2AgNO3 → Cu(NO3)2 + 2 Ag, adding 127 grams of copper to lo

ts of silver nitrate yields 410 grams of silver. What is the percent yield of silver?
I'm desperate.
Chemistry
1 answer:
pishuonlain [190]3 years ago
8 0

Percent yield = (Actual Yield/ Theoretical Yield) x 100

Given, Actual Yield of silver = 410 grams

Given, mass of copper = 127 g

Atomic mass of copper = 63.546 amu

Formula: Moles = mass / atomic mass

Moles of copper = 127 g/ 63.546 amu = 1.998 mol

Based on the given balanced chemical reaction, the molar ratio between Cu: Ag is 1:2

So 1.998 mol of copper should yield (2 mol Ag/ 1 mol Cu) x 1.998 mol of Cu = 3.996 mol

Calculated mol of Ag = 3.996 mol

Atomic mass of silver = 107.8682 amu

Mass of silver = moles x atomic mass = 3.996 mol x 107.8682 amu = 431 g

Based on the math, the theoretical yield = 431 g

Percent yield of silver = (410g/431g) x 100 = 95. 13%

The answer is 95. 13%

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saul85 [17]

Answer: O potássio possui apenas um elétron de valência. ... Considerando que o cálcio possui dois elétrons de valência, requer mais energia para a remoção de um elétron de valência. Devido a esse potássio, é mais reativo que o cálcio.

Explanation:

4 0
3 years ago
0.450 mol of aluminum hydroxide is allowed to react with 0.550 mol of sulfuric acid; the reaction which ensues is: 2Al(OH)3(s) +
Veseljchak [2.6K]

Answer:

The answer to your question is 1.1 moles of water

Explanation:

                     2Al(OH)₃  +   3H₂SO₄   ⇒   Al₂(SO₄)₃  +   6H₂O

                       0.45 mol      0.55 mol                                ?

Process

1.- Calculate the limiting reactant

Theoretical proportion

       Al(OH)₃ / H₂SO₄ = 2/3 = 0.667

Experimental proportion

       Al(OH)₃ / H₂SO₄ = 0.45 / 0.55 = 0.81

From the proportions, we conclude that the limiting reactant is H₂SO₄

2.- Calculate the moles of H₂O

                        3 moles of H₂SO₄ ----------------  6 moles of water

                        0.55 moles of H₂SO₄ -----------    x

                        x = (0.55 x 6) / 3

                        x = 3.3 / 3

                       x = 1.1 moles of water

5 0
3 years ago
A certain solid has a density of 8.0 g/cm3. if 4.0 g of this solid are poured into 4.00 ml of water, which drawing below most cl
Alexandra [31]
Answer is: <span>the volume of water after the solid is added</span> is 4.5 ml.
d(gold) = 8.0 g/cm³; density of gold.
m(gold) = 4 g; mass of gold.
V(gold) = m(gold) ÷ d(gold); volume of gold.
V(gold) = 4 g ÷ 8 g/cm³.
V(gold) = 0.5 cm³ = 0.5 ml.
V(water) = 4.00 ml = 4.00 cm³.
V(flask) = V(gold) + V(water).
V(flask) = 0.5 cm³ + 4 cm³.V = 4.5 cm³.
4 0
3 years ago
Heredity is best described as the
sertanlavr [38]

Answer:

The process by which organisms pass genetic traits on to their offspring.

Explanation:

6 0
3 years ago
Debido a que propiedad un cuerpo flota en el agua y otro no​
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Answer:

cuerpo flota o se hunde es su densidad con respecto a la del líquido en que se sumerge. En cambio, una nuez (densidad = 0.5) flotara en ambos líquidos mientras que una piedra (densidad = 2) se hundirá.

Explanation:

:)

8 0
3 years ago
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