All categories

2 years ago

How many meters per second is 100 meters and 10 seconds

Engineering

1 answer:

Elden [556K]2 years ago

5 0

Answer:

the velocity = 10 m / sec if an object moves 100 m in 10s

You might be interested in

In this image if the ground were removed from the neutral wire what would the voltage to ground be?

zheka24 [161]

Answer:

240

Explanation:

4 0

3 years ago

You installed a new 40 gallon water heater with a 54,000 BTUh burner. The underground water temperature coming into the house is

allochka39001 [22]

Answer:

For most uses you'll want your water heated to 120 F(49 C) In this example you'd need a demand water heater that produces a temperature rise and it will take about 2 hours

7 0

3 years ago

Entor" by

IrinaVladis [17]

Answer:

To generalize your thought about answer. in technology

Explanation:

4 0

3 years ago

A group of statisticians at a local college has asked you to create a set of functions that compute the median and mode of a set

iVinArrow [24]

Answer:

Functions to create a median and mode of a set of numbers

Explanation:

def median(list):

if len(list) == 0:

return 0

list.sort()

midIndex = len(list) / 2

if len(list) % 2 == 1:

return list[midIndex]

else:

return (list[midIndex] + list[midIndex - 1]) / 2

def mean(list):

if len(list) == 0:

return 0

list.sort()

total = 0

for number in list:

total += number

return total / len(list)

def mode(list):

numberDictionary = {}

for digit in list:

number = numberDictionary.get(digit, None)

if number == None:

numberDictionary[digit] = 1

else:

numberDictionary[digit] = number + 1

maxValue = max(numberDictionary.values())

modeList = []

for key in numberDictionary:

if numberDictionary[key] == maxValue:

modeList.append(key)

return modeList

def main():

print "Mean of [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]: ", mean(range(1, 11))

print "Mode of [1, 1, 1, 1, 4, 4]:", mode([1, 1, 1, 1, 4, 4])

print "Median of [1, 2, 3, 4]:", median([1, 2, 3, 4])

main()

3 0

4 years ago

Read 2 more answers

25 gallons of an incompressible liquid exert a force of 70 lbf at the earth’s surface. What force in lbf would 6 gallons of this

jekas [21]

Answer:

froce by 6 gallon liquid on moon surface is 2.86 lbf

Explanation:

given data:

at earth surface

volume of an incompressible liquid = Ve = 25 gallons

force by liquid = 70 lbf

on moon

volume of liquid = Vm = 6 gallons

gravitational acceleration on moon is am = 5.51 ft/s2

Due to incompressibility , the density remain constant.

mass of liquid on surface of earth $= \frac{ force}{ acceleration}$

$mass = \frac{70lbf}{32.2 ft/s2}$

mass = 2.173 pound

$density \rho = \frac{mass}{volume}$

$= \frac{2.173}{25} = 0.0869 pound/ gallon$

froce by 6 gallon liquid on moon surface is

Fm = mass * acceleration

= density* volume * am

= 0.0869 *6* 5.51

= 2.86 lbf

5 0

3 years ago