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3 years ago

What is the difference between kinetic and gravitacional energy?

Physics

1 answer:

kondaur [170]3 years ago

8 0

Answer:

In physics, the kinetic energy (KE) of an object is the energy that it possesses due to its motion

In classical mechanics, the gravitational potential at a location is equal to the work (energy transferred) per unit mass that would be needed to move an object to that location from a fixed reference location. It is analogous to the electric potential with mass playing the role of charge. The reference location, where the potential is zero, is by convention infinitely far away from any mass, resulting in a negative potential at any finite distance.

In mathematics, the gravitational potential is also known as the Newtonian potential and is fundamental in the study of potential theory. It may also be used for solving the electrostatic and magnetostatic fields generated by uniformly charged or polarized ellipsoidal bodies

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Which layer of the atmosphere has the highest density?

fomenos

Answer:

The Troposphere is the lowermost portion of Earth’s atmosphere. It is the densest layer of the atmosphere and contains approximately 75 percent of the mass of the atmosphere and almost all the water vapor and aerosol. The troposphere extends from the Earth’s surface up to the tropopause where the stratosphere begins.

Explanation:

4 0

3 years ago

The voltage or potential difference provides the ____ required for electrons to travel through a circuit

galben [10]

Answer:

a. push

Explanation:

Voltage is the force or pressure that is responsible for pushing the charge or electrons to flow in a closed-looped electrical circuit. This flow of electrons (charge) is called the electric current. It is also defined as the difference in electric potential per unit charge between two points in an electric field.

5 0

3 years ago

One way to cool a gas is to let it expand. When a certain gas under a pressure of 5.00 x 10^6 Pa at 25.°C is allowed to expand t

hichkok12 [17]

Answer:

The final temperature is T2= 5.35°C

Explanation:

Apply the Gay-lussacs's law we have

$\frac{P1}{T1} = \frac{P2}{T2}$

P1, initial pressure= 5.00 x 10^6 Pa

T1, initiation temperature= 25.°C

P2, final pressure= 1.07 x 10^6 Pa

T2, final temperature= ?

$\frac{5.00 * 10^6}{25} =\frac{1.07 *10^6}{T2} \\$

Cross multiplying and making T2 subject of formula we have

$T2 =\frac{1.07 *10^6*25}{5.00 * 10^6} \\\\T2= \frac{26.75}{5} \\T2= 5.35$

T2= 5.35°C

6 0

4 years ago

During which month is the bacteria population just under 1 million?

Thepotemich [5.8K]

D. March because it is just below the 1 million marker on the graph and it is the only one that low.

5 0

3 years ago

A car slows down uniformly from a speed of 22 m/s to rest in 4.0 seconds. How far did it travel in that time

krek1111 [17]

Answer:

$\boxed{\sf Distance \ travelled = 44 \ m}$

Given:

Initial speed (u) = 22 m/s

Final speed (v) = 0 m/s (Rest)

Time taken (t) = 4 seconds

To Find:

Distance travelled by car (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

$\boxed{ \bold{s = (\frac{v + u}{2} )t}}$

By substituting value of v, u & t in the equation we get:

$\sf \implies s = ( \frac{0 + 22}{2} ) \times 4 \\ \\ \sf \implies s = \frac{22}{2} \times 4 \\ \\ \sf \implies s = 11 \times 4 \\ \\ \sf \implies s = 44 \: m$

$\therefore$

Distance travelled by car (s) = 44 m

4 0

4 years ago