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3 years ago

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The NCAA Sportsmanship Award honors students who demonstrate the ideals of sportsmanship, including __________. A. Fairness B. H

onesty C. Respect D. All of the above Please select the best answer from the choices provided. A B C D.

1 answer:

Soloha48 [4]3 years ago

5 0

D: All of the above

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A toy of mass 0.155 kg is undergoing simple harmonic motion (SHM) on the end of a horizontal spring with force constant 305 N/m

zzz [600]

Answer:

$310.38\times 10^{-4}j$

Explanation:

We have given mass m=0.155 kg

Force constant K = 305 N/m

Distance $X=1.25\times 10^{-2}m$

Velocity $v=.305 m/sec$

The total energy at any position of the motion is give by $E=\frac{1}{2}mv^2+KX^2$ here $\frac{1}{2}mv^2$ is energy due to motion and $KX^2$ is energy due to spring elongation

So total energy $E=\frac{1}{2}\times 0.155\times 0.305^2+305\times 0.0125^2=310.38\times 10^{-4}j$

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3 years ago

790 kilometers/hour for a distance of 4,700 kilometers

chubhunter [2.5K]

Answer:

Explanation:

Time = (distance) / (average speed)

Time = (4,700 km) / (790 km/hr) = 5.9494 hours (rounded)

= 5hrs 56min 58 sec (rounded)

(4,700 km) / (1.609344 km/mile) = 2,920 miles

Speed = (distance covered) / (time to cover the distance)

(2,929 miles) / 5.9494 hours) = 491 miles per hour

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3 years ago

Two equal-mass pieces of metal are sitting side by side at the bottom of a deep lake. One piece is aluminum and the other is lea

murzikaleks [220]

Answer:

A. Aluminium

Explanation:

Buoyant force is simple terms refers to the weight of water displaced when an object is immersed in it. The higher the volume of an object, the higher the buoyant force.

From the problem, we have two metals of equal mass, aluminium and lead, of which lead is denser.

density = $\frac{mass}{volume}$

Volume = $\frac{mass}{density}$

This means that the volume of each metal depends on the density, and for the fact that lead is denser , it will have a lower volume than aluminium which means Aluminium will have a greater buoyant force.

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4 years ago

The sound intensity at a distance 2.00 m from a sound source is 5.00 Find the total sound energy emitted by the source in each s

notka56 [123]

Answer:

P = 251, 3 W

Explanation:

The intensity is defined as the power emitted per unit area

I = P / A

Since sound is distributed in all directions spherical shape, the area of a sphere is

A = 4π r²

let's clear the power and replace

P = I A

P = I (4π r²)

let's calculate

P = 5.00 (4π 2²)

P = 251, 3 W

6 0

4 years ago

A child holds onto a string attached to a toy boat and exerts a force of 7.5 N to pull the boat a distance of 9.2 m a long a str

soldi70 [24.7K]

The work that need to do is 66.24 J.

<h3>Explanation :</h3>

Hello guys, before we can count how much the work that needed to pull the toy, we should know how formula to count it first. Because the movement is with the angle, so the formula is :

$\boxed {\bold {W = F \times s \times \cos(\theta)}}$

If :

W = work (J)
F = force (N)
s = shift (m)
θ = elevation angle (°)

We know that :

x = the horizontal shift = 9,2 m
θ = elevation angle = 15°

W = work = ... J

$W = F \times s \times \cos(\theta) \\ W = 7.5 \times 9.2 \times \cos(15) \\ W = 69 \times 0.96 = 66.24 \: J$

So, the work that need to do is 66.24 J.

<u>Subject</u><u> </u><u>:</u><u> </u><u> </u><u>Physics</u><u> </u>

<u>Class</u><u> </u><u>:</u><u> </u><u>Junior</u><u> </u><u>High</u><u> </u><u>School</u><u>/</u><u>Senior</u><u> </u><u>High</u><u> </u><u>School</u><u> </u>

<u>Keyword</u><u> </u><u>:</u><u> </u><u>Work</u><u>;</u><u> </u><u>Force</u><u>;</u><u> </u><u>Shift</u><u>;</u><u> </u><u>and</u><u> </u><u>Elevation</u><u> </u><u>Angle</u><u> </u>

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4 years ago