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enot [183]
3 years ago
15

Electronegativity tends to increase from left to right across a row, because

Chemistry
1 answer:
m_a_m_a [10]3 years ago
7 0
<span>Electronegativity tends to increase from left to right across a row, because </span>the attraction between the nucleus and the valence electrons increases. 
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In determining nuclear binding energy, what is Einstein's equation used to do?
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Basically this is used in calculating the nuclear binding energy by converting the mass defect (calculated first) to energy and if we recall, Einstein's equation E=mc2 is the perfection equation to use because E=mc2 in which E represents units of energy, m represents units of mass, and c 2 is the speed of light squared. 
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If Bert the Bat travels eastward at 540 mph with a tail wind of 6 mph. What is his actual speed?
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Determine whether the reaction will be spontaneous at high temperatures only, at low temperatures only, at all temperatures, or
LiRa [457]

Answer:

The rusting of iron is spontaneous at low temperatures.

Explanation:

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2 years ago
Is aluminum foil a mixture or a pure substance?
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3 years ago
Help asap. <br>How many moles are 5.55x10^25 atoms of Mg
LekaFEV [45]

Answer:

\boxed {\boxed {\sf About \ 92.2 \ moles \ of \ Magnesium}}

Explanation:

To convert from atoms to moles, we must Avogadro's number:

  • 6.022*10²³

This number tells us the amount of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case, it is atoms of magnesium in 1 mole.

  • 6.022 *10²³ atoms Mg / 1 mol mg

Now, let's set up an expression using:

\frac {6.022 * 10^ {23} \ atoms \ Mg}{ 1 \ mol \ Mg}

Multiply this by the given number of atoms.

5.55*10^{25} \ atoms \ Mg *\frac {6.022 * 10^ {23} \ atoms \ Mg}{ 1 \ mol \ Mg}

Flip the fraction so the atoms of magnesium can cancel.

5.55*10^{25} \ atoms \ Mg *\frac { 1 \ mol \ Mg }{6.022 * 10^ {23} \ atoms \ Mg}

5.55*10^{25} *\frac { 1 \ mol \ Mg }{6.022 * 10^ {23}}

Multiply and condense this into 1 fraction.

\frac { 5.55*10^{25} \ mol \ Mg }{6.022 * 10^ {23}}

92.1620724 \ mol \ Mg

The original measurement had 3 significant figures, so our answer must have that many as well. For the number we calculated, that is the tenth place. The 6 in the hundredth place tells us to round the 1 to a 2.

92.2 \ mol \ Mg

It is about <u>92.2 moles of magnesium.</u>

3 0
3 years ago
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