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enot [183]
3 years ago
15

Electronegativity tends to increase from left to right across a row, because

Chemistry
1 answer:
m_a_m_a [10]3 years ago
7 0
<span>Electronegativity tends to increase from left to right across a row, because </span>the attraction between the nucleus and the valence electrons increases. 
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A hot air ballon will rise in air because:
solmaris [256]

Answer: C

Explanation:

Hot air is a lot less dense for a few reasons. Hot air essentially means the particles have more kinetic energy, and move around a lot more. Cold air is dense because the particles move a lot less, have less energy, and are closer together.

7 0
2 years ago
Read 2 more answers
Calculate either [ H 3 O + ] or [ OH − ] for each of the solutions.
STALIN [3.7K]

Answer: Solution A : [H_3O^+]=0.300\times 10^{-7}M

Solution B : [OH^-]=0.107\times 10^{-5}M

Solution C : [OH^-]=0.177\times 10^{-10}M

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration and pOH is calculated by taking negative logarithm of hydroxide ion concentration.

pH=-\log[H_3O^+]

pOH=-log[OH^-}

pH+pOH=14

[H_3O^+][OH^-]=10^{-14}

a. Solution A: [OH^-]=3.33\times 10^{-7}M

[H_3O^+]=\frac{10^{-14}}{3.33\times 10^{-7}}=0.300\times 10^{-7}M

b. Solution B : [H_3O^+]=9.33\times 10^{-9}M

[OH^-]=\frac{10^{-14}}{9.33\times 10^{-9}}=0.107\times 10^{-5}M

c. Solution C : [H_3O^+]=5.65\times 10^{-4}M

[OH^-]=\frac{10^{-14}}{5.65\times 10^{-4}}=0.177\times 10^{-10}M

7 0
3 years ago
Need help read the comment below.
BartSMP [9]

Answer:

Protective fruit

Explanation:

Angiosperm seeds grow in the middle of flower's ovaries and are covered by a defensive fruit.

8 0
3 years ago
The following reaction occurs in aqueous solution: NH4 + (aq) + NO2 - → N2 (g) + 2H2O (l) The data below is obtained at 25°C.
GREYUIT [131]

Answer: The order with respect to NH_4^+ is 1.

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

NH_4^++NO_2^-\rightarrow N_2+2H_2O

Rate=k[NH_4^+]^x[NO_2^-]^y

k= rate constant

x = order with respect to NH_4^+

y = order with respect to ANO_2^-

n = x+y = Total order

From trial 1: 3.2\times 10^{-3}=k[0.0100]^x[0.200]^y    (1)

From trial 2: 6.4\times 10^{-3}=k[0.0200]^x[0.200]^y    (2)

Dividing 2 by 1 :\frac{6.4\times 10^{-3}}{3.2\times 10^{-3}}=\frac{k[0.0100]^x[0.2000]^y}{k[0.0200]^x[0.200]^y}

2=2^x,2^1=2^x therefore x=  1

Thus order with respect to NH_4^+ is 1.

8 0
3 years ago
What are some factors that affect an element's reactivity?
Alexxandr [17]
From what there’s nothing there? :)
7 0
3 years ago
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