1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nata0808 [166]
2 years ago
6

Do the elements in group 7 of the periodic table react with metals to form covalent compounds, ionic compounds, neither, or both

?
Chemistry
1 answer:
Vladimir [108]2 years ago
7 0

Answer:Group 1 elements have 1 valence electron, meaning they have 1 extra electron that can easily be donated to an atom in search of 1 more electron. When they give away that extra electron to form an ionic compound, they become more stable.

For example, Group 7A (Group 17) elements have 7 valence electrons, meaning they need 1 extra electron to be stable. Group 1 and 7A elements make splendid ionic compounds.

Explanation:

You might be interested in
Calculate the volume of a 0.225M solution of KOH required to react with 0.215g of acetic acid.
Sidana [21]
Hope this might help ask me if u have any doubts

7 0
3 years ago
Read 2 more answers
The crystal lattice structure of ionic compounds is responsible for which set of characteristic properties?
Ierofanga [76]
Do u have like choices we can choose from????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????
7 0
3 years ago
Read 2 more answers
Which pair of atoms forms a nonpolar covalent bond? which pair of atoms forms a nonpolar covalent bond? na and cl c and o n and
adelina 88 [10]

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

 

                Less than 0.4 then it is Non Polar Covalent

                

                Between 0.4 and 1.7 then it is Polar Covalent 

            

                Greater than 1.7 then it is Ionic

 

For Na and Cl,

                    E.N of Chlorine       =   3.16

                    E.N of Sodium        =   0.93

                                                   ________

                    E.N Difference             2.23          (Ionic Bond)


For C and O,

                    E.N of Oxygen       =   3.44

                    E.N of Carbon        =   2.55

                                                   ________

                    E.N Difference             0.89          (Polar Covalent Bond)


For N and Cl,

                    E.N of Chlorine      =   3.16

                    E.N of Notrogen     =   3.04

                                                   ________

                    E.N Difference             0.12           (Non-Polar Covalent Bond)


For B and O,

                    E.N of Oxygen        =   3.44

                    E.N of Boron           =   2.04

                                                   ________

                    E.N Difference             1.40          (Polar Covalent Bond)

8 0
4 years ago
Read 2 more answers
Highlighted answer is wrong just need someone to explain it if you can!❤️
lora16 [44]

Answer:

2.7 x 10^-1

Explanation:

The places you move to the left are added to the 10 in negative exponential

7 0
3 years ago
A neutral solution has a(n) _______ amount of hydroxide ions compared to hydrogen ions.
erastovalidia [21]
The answer is 'equal'. Hydroxide ions are OH- and Hydrogen ions are H+. Have you noticed they're opposite charges? Positive + negative = neutral. That's all there is to it :)
4 0
4 years ago
Other questions:
  • What distance does electromagnetic radiation travel in 33 fs?
    10·1 answer
  • What is 19 hundred thousandths in scientific notation
    11·2 answers
  • Which statement is most accurate
    6·2 answers
  • Where on earth did people decide they wanted to go many years ago
    15·1 answer
  • I NEED HELP ASAP, If you help me I’ll give you Brainlist [Calorimetry and specific heat lab]
    5·2 answers
  • How many molecules are there in 39 grams of water
    6·2 answers
  • How many moles (of molecules or formula units) are in each sample?
    9·1 answer
  • Which coefficients will balance the following reaction:
    10·1 answer
  • Which of the following elements have the stronger attraction in a covalent bond with hydrogen, c, Na, O or S?
    5·1 answer
  • 6 Which of the following would provide the best evidence that air is made of matter? A Making a small hole in a tire and measuri
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!