From: Yy Ss Hh 8 different gametes can be formed
- 5 Eye Color Genes = 243 genotypes
- 10 Eye Color Genes= 59049 genotypes
- 20 Eye Color Genes= 3,486,784,401 genotypes
This is further explained below.
<h3>What is a gamete?</h3>
Generally, Gametes are the cells of an organism that are responsible for reproduction. In certain contexts, they are also referred to as egg cells and sperm cells.
The popular word for female gametes is ova, whereas the common name for male gametes is sperm. Ovum and egg cells are other frequent names for female gametes.
Gametes are instances of haploid cells since they only contain a single copy of each chromosome. Haploid cells are described as having only one copy of each chromosome.
In conclusion, For 5 Eye Color Genes
3^n is implored hence
3^5=243 genotypes
Repeating said pattern e have
- 10 Eye Color Genes= 59049 genotypes
- 20 Eye Color Genes= 3,486,784,401 genotypes
Read more about gamete
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CQ
4. Consider the following genotype: Yy Ss Hh. We have now added the gene for height: Tall (H) or Short (h).
a. How many different gamete combinations can be produced?
b. Many traits (phenotypes), like eye color, are controlled by multiple genes. If eye color were controlled by the number of genes indicated below, how many possible genotype combinations would there be in the following scenarios?
a. 5 Eye Color Genes:
b. 10 Eye Color Genes:
c. 20 Eye Color Genes:
Neils bohar proposed his atomic model in 1913.
He describe that's electron travel in a circular orbit surrounds the neuclus of an atom.each orbit has quantized energy and size. Energy is transmitted when an electron jumps from one to other orbit near to nucleus.and it absorb energy when it jumbs away from nucleus.he also said that these electrons are restricted to fixed orbits. In excited state of electron, they absorb or emitt photon with specific wavelength.
Iron doesn't fit because it doesn't have enough atoms or protons in its nucleus so there for it belongs in column 2. <span />
Answer:
ΔSv = 0.1075 KJ/mol.K
Explanation:
Binary solution:
∴ a: solvent
∴ b: solute
in equilibrium:
- μ*(g) = μ(l) = μ* +RTLnXa....chemical potential (μ)
⇒ Ln (1 - Xb) = ΔG/RT
∴ ΔG = ΔHv - TΔSv
⇒ Ln(1 -Xb) = ΔHv/RT - ΔSv/R
∴ Xb → 0:
⇒ Ln(1) = ΔHv/RT - ΔSv/R
∴ T = T*b....normal boiling point
⇒ 0 = ΔHv/RT*b - ΔSv/R
⇒ ΔSv = (R)(ΔHv/RT*b)
⇒ ΔSv = ΔHv/T*b
∴ T*b = 80°C ≅ 353 K
⇒ ΔSv = (38 KJ/mol)/(353 K)
⇒ ΔSv = 0.1075 KJ/mol.K
