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True [87]
3 years ago
8

The rate of change of momentum?

Physics
1 answer:
Blizzard [7]3 years ago
6 0

Answer:

Answer in below and plz mark me as brainlist plz

Explanation:

The rate of change of momentum =tm(v−u) Rate of change of momentum = force applied. Force∝tm(v−u) Velocity is the rate of change of displacement and acceleration is the rate of change of velocity. Impulse is a change in momentum

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blondinia [14]

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Which type of investigation is lised to compare two subiects?
hammer [34]
The answer is comparative.
3 0
3 years ago
A bike accelerates uniformly from rest to a speed of 8.20 m/s over a distance of 45.6 m. Determine the
erica [24]

Answer:

0.737 m/s²

Explanation:

Given:

v₀ = 0 m/s

v = 8.20 m/s

Δx = 45.6 m

Find: a

v² = v₀² + 2aΔx

(8.20 m/s)² = (0 m/s)² + 2a (45.6 m)

a = 0.737 m/s²

8 0
3 years ago
The trunk of a elephant may extend up to 2.2 m. It acts much like an organ pipe only open at one end when the elephant blows air
Talja [164]

Answer:

1) f = 38.63 Hz , 2)   f = 115.9 Hz

Explanation:

The elephant's trunk can be approximated by a tube with a closed end, in pipes the closed ends correspond to nodes and the open ends to antinodes or bellies.

The expression for the wavelengths of this system is

             4L = n λ

              n = 1, 3, 5, 7 ...

               

also let's use the relationship between frequency and wavelength and wave speed

            v = λ f

             f = v / λ

             f = v n / 4L

             f = v / 4L n

1) the fundamental frequency occurs for n = 1

            f = 340/4 2.2 1

            f = 38.63 Hz

2) The first harmonic

           n = 3

            f = 340/4 2.2  3

           f = 115.9 Hz

5 0
3 years ago
A constant electric field with magnitude 1.50 ✕ 103 N/C is pointing in the positive x-direction. An electron is fired from x = −
romanna [79]

Answer:

The speed of electron is 1.5\times10^{7}\ m/s

Explanation:

Given that,

Electric field E=1.50\times10^{3}\ N/C

Distance = -0.0200

The electron's speed has fallen by half when it reaches x = 0.190 m.

Potential energy P.E=5.04\times10^{-17}\ J

Change in potential energy \Delta P.E=-9.60\times10^{-17}\ J as it goes x = 0.190 m to x = -0.210 m

We need to calculate the work done by the electric field

Using formula of work done

W=-eE\Delta x

Put the value into the formula

W=-1.6\times10^{-19}\times1.50\times10^{3}\times(0.190-(-0.0200))

W=-5.04\times10^{-17}\ J

We need to calculate the initial velocity

Using change in kinetic energy,

\Delta K.E = \dfrac{1}{2}m(\dfrac{v}{2})^2+\dfrac{1}{2}mv^2

\Delta K.E=\dfrac{-3mv^2}{8}

Now, using work energy theorem

\Delta K.E=W

\Delta K.E=\Delta U

So, \Delta U=W

Put the value in the equation

\dfrac{-3mv^2}{8}=-5.04\times10^{-17}

v^2=\dfrac{8\times(5.04\times10^{-17})}{3m}

Put the value of m

v=\sqrt{\dfrac{8\times(5.04\times10^{-17})}{3\times9.1\times10^{-31}}}

v=1.21\times10^{7}\ m/s

We need to calculate the change in potential energy

Using given potential energy

\Delta U=-9.60\times10^{-17}-(-5.04\times10^{-17})

\Delta U=-4.56\times10^{-17}\ J

We need to calculate the speed of electron

Using change in energy

\Delta U=-W=-\Delta K.E

\Delta K.E=\Delta U

\dfrac{1}{2}m(v_{f}^2-v_{i}^2)=4.56\times10^{-17}

Put the value into the formula

v_{f}=\sqrt{\dfrac{2\times4.56\times10^{-17}}{9.1\times10^{-31}}+(1.21\times10^{7})^2}

v_{f}=1.5\times10^{7}\ m/s

Hence, The speed of electron is 1.5\times10^{7}\ m/s

4 0
3 years ago
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