Answer:
1. -3
2. -12
3. 20
4. -15
5. 6
6. -15w+5
7. 10
8. C<-26
9.p> -40
10. P> 16
Step-by-step explanation:
~ -9p -17 = 10
-9p = 27
P = -3
~ x/4 -5 = -8
x/4 = -3
x = -12
~ p/5 +6 =10
p/5 = 4
p = 20
~ -2(m-30) =-6m
-2m+60=-6m
4m = -60
m = -15
~ 3n +2=8+2n
n = 6
Answer:

Step-by-step explanation:
Given

Required: Express as a perfect square

Add 10 to both sides


Expand

Factorize:

Factorize:


No they are eaqure to each other.
<span>5 = 15
---------
8 = x
cross multiply
5x =120
5x÷5 = 120÷5
x = 24
Check
5/8 = 15/24
.625 = .625
</span><span>
</span>
Let's actually find the line of best fit...
m=(nΣyx-ΣyΣx)/(nΣx^2-ΣxΣx)
m=(11*836-130*55)/(11*385-3025)
m=2046/1210
m=93/55
b=(Σy-93Σx/55)/n
b=(55Σy-93Σx)/(55n)
b=(7150-5115)/(55*11)
b=185/55, so the line of best fit is:
y=(93x+185)/55
A) The approximate y-intercept (the value of y when x=0) is 185/55≈3.36.
Which means that those who do not practice at all will win about 3.36 times
B) y(13)=(93x+185)/55
y(13)≈25.34
So after 13 months of practice one would expect to win about 25.34 times.