The Magnetic Field in a current carrying wire comes due to flow of electricity . But does the field generate or comes in simulat
2 answers:
Answer:
Electric current produces a magnetic field. This magnetic field can be visualized as a pattern of circular field lines surrounding a wire. ... Magnetic Field Generated by Current: (a) Compasses placed near a long straight current-carrying wire indicate that field lines form circular loops centered on the wire.
Explanation:
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Answer:
Explanation:
If we have a net force F acting on a body of mass m it will experiment an acceleration a. Newton's 2nd Law gives us the relation between these quantities: F=ma.
In our case, we want to calculate the acceleration, so we write:
With the values we have we get:
Answer:
<em>The time interval required to lift the spacecraft to this specified height is 123.94 seconds</em>
Explanation:
Height through which the spacecraft is to be lifted = 32.0 m
Mass of the spacecraft = 260.0 kg
Four crew member each pull with a power of 135 W
18.0% of the mechanical energy is lost to friction.
work done in this situation is proportional to the mechanical energy used to move the spacecraft up
work done = (weight of spacecraft) x (the height through which it is lifted)
but the weight of spacecraft = mg
where m is the mass,
and g is acceleration due to gravity 9.81 m/s
weight of spacecraft = 260 x 9.81 = 2550.6 N
work done on the space craft = weight x height
==> work = 2550.6 x 32 = 81619.2 J
this is equal to the mechanical energy delivered to the system
18.0% of this mechanical energy delivered to the pulley is lost to friction.
this means that
0.18 x 81619.2 = <em>14691.456 J </em> is lost to friction.
Total useful mechanical energy = 81619.2 J - 14691.456 J = 66927.74<em> J</em>
Total power delivered by the crew to do this work = 135 x 4 = 540 W
But we know tat power is the rate at which work is done i.e
where p is the power
where w is the useful work done
t is the time taken to do this work
imputing values, we'll have
540 = 66927.74/t
t = 66927.74/540
time taken t = <em>123.94 seconds</em>
Answer:
a)
b)
Explanation:
The gravitational force on the satellite is calculated with Newton's Gravitation Law:
Where is Earth's mass,
is the satellite mass,
is the distance between their centers, where
is the height of the satellite (from Earth's surface) and
is Earth's radius, and
is the gravitational constant.
a) With these values we then have:
b) And the fraction this force is of the satellite’s weight <em>W=mg</em> is: