Answer:
Option B. Sodium
Explanation:
In the formation of NaCl, sodium loses and electron while chlorine receives the electron as illustrated below:
Na —> Na+ + e- ....... (1)
Cl + e- —> Cl- ......... (2)
Now, combining equation 1 and 2 we have:
Na + Cl + e- —> Na+ + Cl- + e-
Cancelling the electron from both side, we obtained:
Na + Cl —> Na+Cl-
From the above illustration, we see clearly that sodium loses electron
The ammonia gas, having a lower molecular weight than the hydrogen chloride, will diffuse faster and travel a greater length of the tube. Consequently, the white ring of ammonium chloride will form much closer to hydrochloric acid end of the tube. Which in conclusion your answer will be D :)
Answer:
51.54°C the final temperature of the calorimeter contents.
Explanation:
Molarity of HCl= 0.50 M
Volume of HCl= 150.0 mL = 0.150 L
Moles of HCl= n
Molarity of NaOH= 1.00 M
Volume of NaOH= 50.0 mL = 0.050 L
Moles of NaOH= n'
Since moles of NaOH are less than than moles of HCl. so energy release will be for neutralization of 0.050 moles of naOH by 0.050 moles of HCl.
n = 0.050
(1 kJ= 1000 J)
The energy change released during the reaction = 2800 J
Volume of solution = 150.0 mL + 50.0 mL = 200.0 mL
Density of the solution (water) = 1.00g/mL
Mass of the solution , m= 200 mL × 1.00 g/mL = 200 g
Now , calculate the final temperature by the solution from :
where,
q = heat gained = 2800 J
c = specific heat of solution = 
= final temperature = 
= initial temperature = 
Now put all the given values in the above formula, we get:
51.54°C the final temperature of the calorimeter contents.
The answer is electrolytes. Strong electrolytes like strong acids, strong bases and salts dissociate completely into ions when dissolved and no neutral molecules are present in their solution. Weak electrolytes like weak acids and weak bases do not completely ionize in water and some neutral molecules are present in their solution, while nonelectrolytes do not dissociate into ions when in solution at all.
