Answer : The volume of 6M NaOH stock solution is, 16.7 mL
Explanation :
To calculate the volume of NaOH stock solution, we use the equation given by neutralization reaction:
![M_1V_1=M_2V_2](https://tex.z-dn.net/?f=M_1V_1%3DM_2V_2)
where,
are the molarity and volume of NaOH stock solution.
are the molarity and volume of NaOH.
We are given:
![M_1=6M\\V_1=?\\M_2=0.2M\\V_2=500mL](https://tex.z-dn.net/?f=M_1%3D6M%5C%5CV_1%3D%3F%5C%5CM_2%3D0.2M%5C%5CV_2%3D500mL)
Putting values in above equation, we get:
![6M\times V_1=0.2M\times 500mL\\\\V_1=16.7mL](https://tex.z-dn.net/?f=6M%5Ctimes%20V_1%3D0.2M%5Ctimes%20500mL%5C%5C%5C%5CV_1%3D16.7mL)
Thus, the volume of 6M NaOH stock solution is, 16.7 mL
Explanation:
The weak intermolecular forces which can arise either between nucleus and electrons or between electron-electron are known as dispersion forces. These forces are also known as London dispersion forces and these are temporary in nature.
Therefore, more is the surface area occupied by the carbon chain more will be the dispersion forces present in it. Hence, less is the surface area occupied by a molecule less will be the dispersion forces present in it.
Hence, the given molecules are organized from largest to smallest dispersion forces as follows.
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> ![CH4](https://tex.z-dn.net/?f=CH4)