The element that is the transition metal is Cr or chromium
Answer:
The answer to your question is: 516 g of water
Explanation:
2 C₇H₁₄ + 21 O₂ → 14 CO₂ + 14 H₂O
8 moles 43 moles
Process
1.- Find the limiting reactant
Ratio theoretical O₂ / C₇H₁₄ = 21 / 2 = 10.5
Ratio experimental O₂ / C₇H₁₄ = 43 / 8 = 5.3
As the ratio diminishes the limiting reactant is O₂.
2.- Calculate the moles of water
21 moles of O₂ ------------- 14 moles of water
43 moles of O₂ ------------ x
x = (43 x 14) / 21
x = 28.67 moles of water
3.- Calculate the grams of water
Molecular mass of water= 18g
18 g ------------------------ 1 mol of water
x ------------------------ 28.67 moles of water
x = (28.67 x 18) / 1
x = 516 g of water
Answer:
0.04167mole
Explanation:
To convert gram to mole,
C6H12O6
C - 12
H - 1
O - 6
There are 6 moles of C, 12 mole of H and 6 mole of O
Therefore, multiply each number of mole by the mass of each element
C - 12 * 6 = 72
H - 1 * 12 = 12
O - 16 * 6 = 96
The molar mass of C6H12O6 = 72 + 12 + 96
= 180g/mol
Dividing the number of mass by the mm
= 7.50g / 180g/mol
= 0.04167 mole
Answer:test hypothesis using an experiment.
Explanation:
