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solong [7]
2 years ago
13

What is the difference between speed and velocity?​

Physics
2 answers:
STatiana [176]2 years ago
8 0

\huge \sf \underline{ \color{green}Ⱥnswɇɍ : }

  • Speed is a scalar quantity.

  • Speed ascertain how fast a body moves.

  • \large \sf \: Speed =  \frac{distance}{time}

____________________________

  • Velocity is a vector quantity.

  • Velocity Ascertain the object speed & the director on it takes while moving.

  • \large \sf \: velocity =  \frac{displacement}{time}

<h3>Hope Helps~</h3>
ikadub [295]2 years ago
6 0

The difference between the two concepts lies in the type of magnitude they represent, speed is a scalar magnitude, while velocity is a vectorial magnitude.

<h3>What is speed?</h3>

It is the variation of distance in a certain time as a consequence of the movement of a mobile element.

<h3>What is velocity?</h3>

It is the vectorial magnitude that shows and expresses the variation in terms of position of an object and as a function of time.

Therefore, we can conclude that speed is a scalar magnitude that determines the ratio of the distance traveled by a body and velocity is a vectorial magnitude that expresses the relationship between the space traveled by an object, the time used for it and its direction.

Learn more about the difference between speed and velocity here: brainly.com/question/16942553

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3 years ago
A circular flat coil that has N turns, encloses an area A, and carries a current i, has its central axis parallel to a uniform m
Aneli [31]

Answer:

A. Zero

Explanation:

The force on a coil of N turns, enclosing an area, A and carrying a current I in the presence of a magnetic field B, is :

F = N * I * A * B * sinθ

Where θ is the angle between the normal of the enclosed area and the magnetic field.

Since the normal of the area is parallel to the magnetic field, θ = 0

Hence:

F = NIABsin0

F = 0 or Zero

4 0
3 years ago
A banked circular highway curve is designed for traffic moving at 58 km/h. The radius of the curve is 201 m. Traffic is moving a
skelet666 [1.2K]

Answer:0.077

Explanation:

Given

banked designed for traffic moving at 58 km/h\approx 16.11 m/s

Radius of the curve 201 m

Actual traffic velocity =37 km/h approx  10.27 m/s

For banking of road

tan\theta =\frac{v^2}{rg}

tan\theta =\frac{16.11^2}{201\times 9.81}

\theta =7.49^{\circ}

Centripetal acceleration is given by

a=\frac{v^2}{r}

Taking component of centripetal acceleration

along and perpendicular to surface

a_{parallel}=\frac{v^2cos\theta }{r}

a_{perpendicular}=\frac{v^2sin\theta }{r}

From FBD

mgsin\theta -f_s=ma_{parallel}

f_s=mgsin\theta -ma_{parallel}----1

where f_s is frictional force

N-mgcos\theta =ma_{perpedicular}

N=mgcos\theta +ma_{perpedicular}----2

and we know coefficient of friction is given by

\mu =\frac{f_s}{N}

\mu =\frac{mgsin\theta -ma_{parallel}}{mgcos\theta +ma_{perpedicular}}

\mu =\frac{gsin\theta -\frac{v^2cos\theta }{r}}{gcos\theta +\frac{v^2sin\theta }{r}}

\mu =\frac{1.2804-0.5202}{9.726+0.068}

\mu =0.077

7 0
3 years ago
The resistance, R, of a wire varies directly as its length and inversely as the square of its diameter. If the resistance of a w
lbvjy [14]

R is proportional to the length of the wire:

R ∝ length

R is also proportional to the inverse square of the diameter:

R ∝ 1/diameter²

The resistance of a wire 2700ft long with a diameter of 0.26in is 9850Ω. Now let's change the shape of the wire, adding and subtracting material as we go along, such that the wire is now 2800ft and has a diameter of 0.1in.

Calculate the scale factor due to the changed length:

k₁ = 2800/2700 = 1.037

Scale factor due to changed diameter:

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Multiply the original resistance by these factors to get the new resistance:

R = R₀k₁k₂

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R = 9850(1.037)(6.76)

R = 69049.682Ω

Round to the nearest hundredth:

R = 69049.68Ω

8 0
3 years ago
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Angelina_Jolie [31]

Answer:

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Explanation:

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