16.4 grams is the mass of solute in a 500 mL solution of 0.200 M
.
sodium phosphate
Explanation:
Given data about sodium phosphate
atomic mass of Na3PO4 = 164 grams/mole
volume of the solution = 500 ml or 0.5 litres
molarity of sodium phosphate solution = 0.200 M
The formula for molarity will be used here to know the mass dissolved in the given volume of the solution:
The formula is
molarity = 
putting the values in the equation, we get
molarity x volume = number of moles
0.200 X 0.5= number of moles
number of moles = 0.1 moles
Atomic mass x number of moles = mass
putting the values in the above equation
164 x 0.1 = 16.4 grams
16.4 grams of sodium phosphate is present in 0.5 L of the solution to make a 0.2 M solution.
The balanced equation will read:
Pb(NO3)2 (aq) + LiSO4 (aq) ➡️ PbSO4 (s) + 2️⃣LiNO3 (aq)
have a great day!!
Q = ?
Cp = 0.397 J/ºC
Δt = 40.3 - 21.0<span> => 19.3</span><span> ºC</span>
m = 15.2 g
Q = m x Cp x Δt
Q = 15.2 x 0.397 x 19.3
Q ≈ 116.46 J
<span>hope this helps! </span>
Explanation:
An acid is a substance that ionizes to produce excess hydrogen ion in solutions.
- A concentrated acid contains a high amount of hydrogen ions in solution compared to other ions.
- Such solutions usually ionizes completely.
- A dilute solution contains a high proportion of water and with low amount of hydrogen ions.
- They do not ionize easily and as fast as strong acids.
Answer:
The empirical formula is C₂H₃
Explanation:
The empirical formula of a chemical compound is defined as the simplest positive integer ratio of atoms present in a compound.
The reaction of combustion for a CₐHₓ is:
CₐHₓ + (a+x/4) O₂ → a CO₂ + ˣ/₂ H₂O
The moles obtained are
15,3 g of CO₂ × 
= 0,3476 moles of CO₂≡moles of C
4,70 g of H₂O × 
= 0,2608 moles of H₂O × 2 = 0,5216 moles of H.
The ratio H:C is 0,5216/0,3476= 1,5. That means you have 1,5 H per 1C, that is the same than 3H per 2C. Thus, empirical formula is:
C₂H₃
I hope it helps!
