Answer:
Wt Avg At Mass = 39.0229 amu
Explanation:
The Weight Average Atomic Mass in atomic mass units (amu) is the sum of the Weight Average Mass contributions of each isotopic mass. That is,
Wt. Avg. At. Mass (amu) = ∑ Wt. Avg. Contributions of each isotopic mass
Wt. Avg. Contribution = fractional abundance x isotopic mass(amu)
For this problem data:
Isotope %Abundance fractional Isotopic Wt Avg Isotopic
abundance mass(amu) Contribution (amu)
1 9.67% 0.0967 38 3.6746 amu
2 78.68% 0.7868 39 30.6852 amu
3 11.34% 0.1134 40 4.5360 amu
4 0.31% 0.0031 41 0.1271 amu
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Wt. Avg. Atomic Mass (amu) = ∑ Wt. Avg. Contributions = 39.0229 amu
The percent by mass : 6.3%
<h3>Further explanation</h3>
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
mass of potassium nitrate = 8.4 g⇒solute
- mass of solution = mass of solute+mass of solvent(water)
mass of potassium nitrate + mass of water = 8.4 g + 125 g =133.4 g
Percent by mass of the solute :
Answer:
Explanation:
C. A proton and an electron
<span>Na --> Na+ + e- E = +2.71
2H2O + 2 e- --> H2 + 2 OH- E = -0.83
Delta E = 2.71 - 0.83 = 1.88 Volts
You know the reaction is spontaneous because Ecell is positive.
Delta Go = - n F Delta E
Delta Go = - 2mol (96485 J/volt mol) (1.88 V)
Delta go = -3.62X10^5 J/mol = -326 kJ/mol
Yes, it is VERY spontaneous.</span>