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2 years ago

Define and explain the Police Power

Physics

1 answer:

Allushta [10]2 years ago

6 0

Answer:

Police powers are the fundamental ability of a government to enact laws to coerce its citizenry for the public good, although the term eludes an exact definition. The term does not directly relate to the common connotation of police as officers charged with maintaining public order, but rather to broad governmental regulatory power. Berman v. Parker, a 1954 U.S. Supreme Court case, stated that “public safety, public health, morality, peace and quiet, law and order. . . are some of the more conspicuous examples of the traditional application of the police power”; while recognizing that “an attempt to define police powers reach or trace its outer limits is fruitless.”

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A 120 W lightbulb and a 90 W lightbulb each operate at a voltage of 120 V. Part A Which bulb carries more current? Which bulb ca

uysha [10]

Answer:

120 W lightbulb

Explanation:

Let the two lightbulb be A and B respectively.

Given the following data;

Power A = 120W

Power B = 90W

Voltage = 120V

To find the current flowing through each lightbulb;

a. For lightbulb A

Power = current * voltage

120 = current * 120

Current = 120/120

Current = 1 Ampere.

b. For lightbulb B

Current = power/voltage

Current = 90/120

Current = 0.75 Amperes

Therefore, the lightbulb that carries more current is A with 1 Ampere.

7 0

3 years ago

What type of transfer of solar energy helps to contribute to the "greenhouse effect"

Paul [167]

The greenhouse effect occurs when Earth's atmosphere traps solarradiation ... infrared (IR) and other types of radiation that are invisible to the human eye. UV radiation has a shorter wavelength and a higher energy level

8 0

3 years ago

Read 2 more answers

A double slit experiment is conducted in air using a laser at 532nm and a slit separation of 20um. What happens to the fringe sp

Reika [66]

Answer:

Option B - The fringe spacing will increase

Explanation:

We are given;

Wavelength; λ = 532nm

slit separation; d = 20um

For double-slit experiment, the fringe width is given by the expression;

β = λD/d

Where;

β is the fringe width

λ is the wavelength

D is the distance between the screen and the slit

d is the slit separation

Now, when immersed in water, the slit separation distance will decrease.

Now, from the fringe width equation, when "d" decreases, it means that we will have a bigger value of fringe width.

Thus, as slit separation decreases, the fringe width increases.

3 0

3 years ago

An electric field of 4.0 μV/m is induced at a point 2.0 cm from the axis of a long solenoid (radius = 3.0 cm, 800 turns/m). At w

vagabundo [1.1K]

Answer:

The rate of current in the solenoid is 0.398 A/s

Explanation:

Given that,

Electric field $E = 4.0\ \mu V/m$

Distance = 2.0 cm

Radius = 3.0 cm

Number of turns per unit length = 800

We need to calculate the rate of current

Using formula of electric field for solenoid

$E = \dfrac{x}{2}\mu_{0}n\dfrac{dI}{dt}$

Where, x = distance

n = number of turns per unit length

E = electric field

r = radius

Put the value into the formula

$4.0\times10^{-6}=\dfrac{2.0\times10^{-2}}{2}\times4\pi\times10^{-7}\times800\times\dfrac{dI}{dt}$

$\dfrac{dI}{dt}=\dfrac{4.0\times10^{-6}\times2}{2.0\times10^{-2}\times4\pi\times10^{-7}\times800}$

$\dfrac{dI}{dt}=0.397\ A/s$

Hence, The rate of current in the solenoid is 0.398 A/s.

6 0

4 years ago

A small box of mass m1 is sitting on a board of mass m2 and length L. The board rests on a frictionless horizontal surface. The

inn [45]

Answer: Fmin = (m₁ + m₂) μsg

Explanation:

To begin, we would first define the parameters given in the question.

Mass of the box = m₁

Mass of the board = m₂

We have a Frictionless surface given that Fr is acting as the frictional force between the box and the board.

from our definition of force, i.e. the the frictional force against friction experienced by the box, we have

Fr = m₁a ...................(1)

Also considering the force between the box and the board gives;

Fr = μsm₁g .................(2)

therefore equating both (1) and (2) we get

m₁a = μsm₁g

eliminating like terms we get

a = μsg

To solve for the minimum force Fmin that must be applied to the board in order to pull the board out from under the box, we have

Fmin = (m₁ + m₂) a ...........(3)

where a = μsg, substituting gives

Fmin = (m₁ + m₂) μsg

cheers i hope this helps

4 0

3 years ago