All categories

3 years ago

What is the mass of a baseball that has a kinetic energy of 100 J and travel at 5 m/s

Physics

2 answers:

djyliett [7]3 years ago

8 0

Mass = kinetic energy * 2 / velocity^2

=> mass= 100 * 2 / 5^2

= 200 / 25 = 8 kg

in short , your answer is 8 kg

serious [3.7K]3 years ago

4 0

K.E= 1/2 mv²
So, m= K..E*2/v²
∴ m= 100 *2/ 25
m=8 Js²/m
As, the unit of K.E and velocities are in SI so unit of mass would also be in SI i.e, kg
So, m=8 kg

You might be interested in

What charge do electrons have?<br> A. no charge<br> B. a positive charge<br> C. a negative charge

Mandarinka [93]

Electrons have a negative charge.

5 0

2 years ago

When light encounters a barrier with slits cut it in it, the light will bend through the slits creating a pattern like that seen

lawyer [7]

Answer:

reflection

Explanation:

an example would be looking in the mirror

8 0

3 years ago

Read 2 more answers

In a real system of levers, wheels, or pulleys, the AMA is less than the IMA because _____.

pickupchik [31]

In a real system of levers, wheels, or pulleys, the AMA is less than the IMA because of friction.
AMA (Actual mechanical advantage) is found by dividing output force by effort force. The actual mechanical advantage will always be less than the ideal mechanical advantage. The ideal mechanical advantage assumes perfect efficiency which doesn't account for friction, while actual mechanical advantage does. Therefore; the IMA is always greater than the actual mechanical advantage because all machines must overcome friction.

5 0

3 years ago

Kinetic friction acts on a baseball player sliding into first base. Will the player's velocity change?

Law Incorporation [45]

Yes, his velocity will decrease the further he slides.

7 0

3 years ago

Suppose we take a 1 m long uniform bar and support it at the 33 cm mark. Hanging a 0.15 kg mass on the short end of the beam res

MakcuM [25]

Answer:

The mass of the beam is 0.074 kg

Explanation:

Given;

length of the uniform bar, = 1m = 100 cm

Set up this system with the given mass and support;

0-----------------33cm-----------------------------------100cm

↓ Δ ↓

0.15kg m

Where;

m is mass of the uniform bar

Apply the principle of moment to determine the value of "m"

sum of anticlockwise moment = sum of clockwise moment

0.15kg(33 - 0) = m(100 - 33)

0.15(33) = m(67)

$m = \frac{0.15kg(33 \ cm)}{67 \ cm}\\\\m = 0.074 \ kg$

Therefore, the mass of the beam is 0.074 kg

8 0

3 years ago