Answer:
yield = 8501.96 g H3PO4
Explanation:
2344.44 g H20 × (1 mol H2O/18.01528 g H20)
= 130.14 mol H20
130.14 mol H2O × (4 mol H3PO4/6 mol H2O)
= 86.76 mol H3PO4
86.76 mol H3PO4 × (97.994 g H3PO4/1 mol H3PO4)
= 8501.96 g H3PO4
Plasma if fourth phase of matter
Plasma technique is used where fire is used
So the correct answer is arc welder
For this problem, we use the Faradays law to relate the mass electroplated and the current passed through. We do as follows:
60.1 g (1 mol / 196.67 g) (1 mol e- / 1 mol Au) ( 96500 C / 1 mol e- ) = 29486.25 C
Q = It
29486.25 = 5t
t = 5897.85 s = 98.30 min
Hope this answers the question.
Answer:
27.7 grams of Li
0.140 moles of Co
0.158 moles of K
59.9 grams of As
8.00x10⁻⁹ moles of U
142.8 moles of H
0.0199 moles of O
0.666 moles of Pb
Explanation:
Mass / Molar mass = Mol
Mol . Molar mass = Mass
3.99 m . 6.94 g/m = 27.7 grams of Li
8.28 g / 58.93 g/m = 0.140 moles of Co
6.17 g / 39.1 g/m = 0.158 moles of K
0.8 mol . 74.92 g/m = 59.9 grams of As
6.02x10²³ (NA) particles are contained in 1 mol
6.02x10²³ are contained in 1 mol U____ 1 mol H ____ 1 mol O ___ 1 mol Pb
4.82x10¹⁵ atoms U ____ 4.82x10¹⁵/ 6.02x10²³ = 8.00x10⁻⁹ moles of U
8.60x10²⁵atoms H ____ 8.60x10²⁵ / 6.02x10²³ = 142.8 moles of H
1.20x10²² atoms O ____ 1.20x10²² / 6.02x10²³ = 0.0199 moles of O
4.01x10²³ atoms Pb ____ 4.01x10²³ / 6.02x10²³ = 0.666 moles of Pb
Water is amphoteric with both the acidic and basic characters.
<u>Explanation:</u>
As per the Bronsted Lowry theory of acids and bases,
Water has its own ability to either donate or accept hydrogen ions or protons.
- If it accepts a proton then it is termed as basic
- To accept a proton it should have a lone pair of electrons.
- If it donates a proton then it is termed as acidic
- If the water has the ability to accept as well as donating proton then it has both the acidic and basic characters and so it is termed as amphoteric in nature.