the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
2x+6 is the base
Then the equation is logarithm of 144 on basis 2x + 6 = 2
Then [2x + 6]^2 = 144
Now expand the square binomial
4x^2 + 24x + 36 = 144
4x^2 + 24x + 36 - 144 = 0
4x^2 + 24x - 108 = 0
Divide by 4
x^2 + 6x - 27 = 0
Factor: (x + 9 ) (x - 3) = 0
x = -9 and x = 3
The only valid is x = 3, because x = -9 yields 2x + 6 = - 12 and the logarithm function cannot have negative basis.
Then the answer is x = 3.
Answer:
Step-by-step explanation:
Volume =
r=4
h=3
Answer:
14
Step-by-step explanation:
(-2) + (-15) - (-3)
~Simplify
-2 - 15 + 3
~Subtract
-17 + 3
~Add
-14
Best of Luck!
