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kozerog [31]
3 years ago
15

Identify the action and reaction forces in the following situations: a) Earth attracts the Moon, b) a boy kicks a football, c) a

rocket accelerates upward, d) a car accelerates forward, e) a high jumper leaps, and f) a bullet is shot from a gun.
Physics
1 answer:
jeka943 years ago
7 0

Answer:

#See solution for details

Explanation:

a. Action: Earth pulls on the Moon, reaction: Moon pulls on Earth;

b. Action: foot applies force to ball, reaction: ball applies force to foot;

c. Action: rocket pushes on gas, reaction: gas pushes back on rocket;

d. Action: car tires push backward on road, reaction: road pushes forward on tires;

e. Action: jumper pushes down on ground, reaction: ground pushes up on jumper;

f. Action: gun pushes forward on bullet, reaction: bullet pushes backward on gun

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It is most accurate to say that body mass index (BMI) provides information about an individual's height-weight ratio. The correct answer is B.
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An upward force of 32.6 N is applied via a string to lift a ball with a mass of 2.8 kg. (a) What is the gravitational force acti
Igoryamba

Answer:

a) Fg = -27.4 N

b) Fnet = 5.2 N

c) a = 1.9 m/s2

Explanation:

a)

  • There are two forces acting on the ball, one directed upward (assuming this direction as positive, along the y-axis) which is the tension on the string (lifting force), and another aimed downward, which is the attractive force due to gravity.
  • Applying the Newton's Universal Law of Gravitation to a mass close to the surface of the Earth (in this case the ball), we can take the acceleration due to gravity like a constant, that we call by convention g, equal to -9.8 m/s2.
  • So, we can write the following expression for Fg:

       F_{g} = m*g = 2.8 kg*(-9.8m/s2) = -27.4 N (1)

b)

  • The net force on the ball, will be just the difference between the lifting force (32.6 N) and the force due to gravity, Fg:

       F_{net} = T -F_{g} = 32.6 N - 27.4 N = 5.2 N  (2)

c)

  • According Newton's 2nd Law, the acceleration caused by a net force on a point mass (we can take the ball as one) is given by the following expression:

       a = \frac{F_{net} }{m} = \frac{5.2N}{2.8kg} = 1.9 m/s2  (3)

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3 years ago
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9.0 km/h due east. Runner B is initia
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Answer:

From the data we know that runner A and runner B are 11 km apart from the start because (6+5) km

So the runner from the east direction has distance as unknown km, rate= 9 k/h ; time= d/r=x/9 hr

So runner towards the west will be

distance = 11-x, rate= 8 k/h, time = d/r = (11-x)/8

So equating east and west time we have

x/9= (11-x)/8

8x=99-9x

17x=99

x=5.92 km

That is the distance covered by runner towards the east and he will meet the runner toward the west at

6-5.92=0.08 km west of the flagpole.

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3 years ago
9As a student walks downhill at constant speed, his gravitational potential energy
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Answer:

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Explanation:

sgnsfnNCzgnzncxmhshdgNdfjBFzktajfskgskgzngzngzgnzngzngzfNFzngzngznfzngzngzngzng

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Determine the gradient and the co-ordinates of the x and y intercept of line whose equation is 2y + 3x = 1​
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Answer:

The x - intercept is 1/3

The y - intercept is 1/2

The gradient is -3/2

Explanation:

To find the x - intercept of the equation 2y + 3x = 1, we find the value of x when y = 0. So,

2y + 3x = 1

2(0) + 3x = 1

0 + 3x = 1

3x = 1

x = 1/3

So, the x - intercept is 1/3

To find the y - intercept of the equation 2y + 3x = 1, we find the value of y when x = 0. So,

2y + 3x = 1

2y + 3(0) = 1

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So, the y - intercept is 1/2

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So, 2y + 3x = 1

2y = -3x + 1

y = -3x/2 + 1/2

The coefficient of x which equals -3/2 is the gradient.

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